Answer:
See the proof below.
Step-by-step explanation:
For this case we need to proof that: Let be independent random variables with a common CDF . Let be their ECDF and let F any CDF. If then
Proof
Let different values in the set {} and we can assume that represent the number of that are equal to .
We can define and assuming the probability .
For the case when for any then we have that the
And for the case when all and for at least one we know that for all the possible values . So then we can define the following ratio like this:
So then we have that:
And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that
And with that we complete the proof.
Answer:80
Step-by-step explanation:if you multiply a times 20 to get 5, you have to multiply b times 20 to get 80
a. because to divide 6 1/4 and 3 you need to make the improper fraction a mixed number so the equation is 25/4 / 3/1 then you get the recipricol of 3 witch is 1/3 then you multiply 1/3 x 25/4 whitch is 25/12=2 1/12
The answer would be 50% or 1/2