Answer:
False
Step-by-step explanation:
You substitute 
for the second equation.
Then you have to distribute 
.
Combine like terms.
Let x represent the number of shirts. Let y represent the number of pens.
If shirts are on sale for $11.99 each, then x shirts cost $11.99x.
If pants are on sale for $12.99 each, then y pants cost $12.99y.
The total cost is $(11.99x+12.99y).
Sarah can spend up to $65. Then an inequality that represents this situation is
11.99x+12.99y≤65 (this inequality holds when Sarah can spend $65 too)
or
11.99x+12.99y<65 (this inequality holds when Sarah can spend less than $65).
Answer:lol
Step-by-step explanation:
hahaha
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
10, 15, 20, 25, 30.... and so on
