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Dahasolnce [82]
3 years ago
12

I need help it is a multiple Choice question

Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

6 m

.006 km  

6,000 mm

Step-by-step explanation:

Let's look at some conversions real quick:

1 cm --> 10 mm (multiply cm by 10)

1 cm --> 0.00001 km (divide cm by 100000)

1cm --> 0.01 m (divide cm by 100)

Now that this is laid out, lets do these conversions for 600 cm.

Meters (m) = 600/100 = 6 meters

Kilometers (km) = 600/100000 = .006km

Millimeters (mm) = 600 * 10 = 6,000 mm

<em>I hope this helps!!</em>

<em>- Kay :) </em>

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Answer:

3\frac{3}5}

Step-by-step explanation:

Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

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Simplify the expression. <br> -4b + (-9k) -6 - 3b + 12
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U meet all 3 lines to the middle. Hope this helps
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Two buildings are facing each other on a road of width 12 metre . From the top of the first building, which is 10 metre high , t
Karo-lina-s [1.5K]

Answer:

\displaystyle 10 + 12\sqrt{3} <em>metres</em>

Step-by-step explanation:

You are finding the <em>height</em><em> </em>of the building with an angle of elevation, therefore we need to solve for <em>EC</em><em> </em>to add it to <em>BA</em><em> </em>[10 metres] and use TRIGONOMETRIC RATIOS to arrive at our conclusion. Just in case you have forgotten what they were, here they are:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

We can now solve for <em>EC</em>:

\displaystyle cot\:60 = \frac{12}{EC} → ECcot\:60 = 12 \\ \\ \frac{ECcot\:60}{cot\:60} = \frac{12}{cot\:60} → 12\sqrt{3} = EC

<em>OR</em>

\displaystyle tan\:60 = \frac{EC}{12} → 12tan\:60 = EC → 12\sqrt{3} = EC

Now that you have solved for <em>EC</em>, you can now add it to your original 10 metres to get \displaystyle 10 + 12\sqrt{3} <em>metres</em>. As a decimal, you would get \displaystyle 30,78460969... <em>metres</em>. You can go ahead and round this off if necessary.

** The reason why the <em>cotangent</em><em> </em>[or <em>tangent</em>] ratio was used was because <em>EA</em><em> </em>is equivalent to <em>DB</em> by the definition of a rectangle. It has two pairs of parallel and congruent sides with <em>four</em><em> </em><em>right</em><em> </em><em>angles</em>. Plus, that is the <em>adjacent</em><em> </em><em>side</em><em> </em>of the triangle, while <em>EC</em><em> </em>is the <em>opposite</em><em> </em><em>side</em><em> </em>of the triangle, so we knew our ratios were correct.

I am joyous to assist you at any time.

8 0
3 years ago
Please help me as soon as possible. Thank you
gavmur [86]
2x + y = 3 is the blue boundary line...the shading is below the line which means 2x + y is less than or equal to 3

y - x = 2 is the red boundary line... the shading is above the line which means
y - x is greater than or equal to 2

ANSWER: 2x + y is less than or equal to 3 and y - x is greater than or equal to 2
5 0
4 years ago
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