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Sladkaya [172]
3 years ago
13

Can someone please help me, ty!! (Will mark brainliest)

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer:

im gonna say 4 if im wrong its my fault

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A monopolist faces the following demand curve, marginal revenue curve, total cost curve and marginal cost curve for its product:
Ad libitum [116K]

The total profit that is earned is 4512.5

<h3>How to solve for the profit that is earned</h3>

100 - q = 0

q = 100

Maximization is where q = 0

MR = mc

100 - q = 5

such that q = 95

Price would be  100 -0.5(95)

= 100 - 47.5

= 52.5

Profit earned would be

= 95*52.5 -5*95

= 4512.5

Read more on profit maximization here: brainly.com/question/13464288

#SPJ4

7 0
2 years ago
Write an equation for each graph in a slope<br> Intercept form
artcher [175]

Answer:

y=2x-3

Step-by-step explanation:

Y-intercept can be read off the graph.

Slope can be determined using the formula:

y2-y1 divided by x2-x1 (Substitute co-ordinates)

6 0
3 years ago
Read 2 more answers
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
3 years ago
According to exponent rules, when we multiply the same base we _____ the exponents
Mazyrski [523]

Answer:

Add

Step-by-step explanation:

When MULTIPLY exponents with same base, you Keep the base and + ADD the exponents.

4 0
3 years ago
Read 2 more answers
Karla saved 2/3 of her allowance. Olga saved 25% of her allowance. Harley saved 1/8 of her allowance. And, Kayla saved 0.40 of h
Fittoniya [83]

Answer:

0.125, 0.25, 0.4, 0.666...

Harley, Olga, Kayla, Karla

Step-by-step explanation:

Change each number into a decimal, then compare them.

Karla saved 2/3 = 0.666...

Olga saved 25% = 0.25

Harley saved 1/8 = 0.125

Kayla saved 0.40 = 0.4

From least to greatest:

0.125, 0.25, 0.4, 0.666...

Harley, Olga, Kayla, Karla

3 0
2 years ago
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