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ss7ja [257]
3 years ago
8

How do you know a quadratic function has exactly one zero?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Answer:

b)

Step-by-step explanation:

y = x² + 6x + 9 = (x + 3)(x + 3)

(x + 3)(x + 3) = 0, x = - 3,

or

you can find  D =b² - 4ac

y = x² + 6x + 9

a = 1, b = 6, c = 9

D = 6² - 4*1*9 = 36- 36= 0

When D =0, a quadratic function has exactly one zero.

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Malcolm wanted to build a dog run with an area of 64. What is the smallest perimeter the dog run could be
Brrunno [24]
The shape with the most area with the smallest perimiter is the circle
first find the radius
then find the circumfernece(permiter)
so
area=64
shape=circle
area of circle=pi times r^2
pi times r^2=64
divide both sides by pi (aprox 3.141592)
r^2=20.3718
square root both sdies
r=4.5

circumference=2pi times r
2 times 3.141592 times 4.5=28.36
perimiter is 28.36
3 0
2 years ago
Plz ANWSER no one else will amwser this
RoseWind [281]

Answer:

1. 80.5

2. 432

3. 310.5

4. 26

Step-by-step explanation:

6 0
3 years ago
Need a gf then i got you
Novosadov [1.4K]
Hi i’m answering on here so i can ask someone something through the messages bc i haven’t answered enough questions
6 0
3 years ago
Read 2 more answers
A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i
Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

2=\frac{1+x_{2} }{2}\\  4=1+x_{2}\\  4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0

So (12,0) it is the other endpoint.

Take a look at the graph below:

8 0
3 years ago
hi people i suck at math and is in 10th grade i have a question if you start at 5,2 and move 3 units left and 2 units up what do
irina [24]

Answer:

(2,4)

Step-by-step explanation:

left( - ) and right( + ) (x axes)

up( + ) and down( - ) (y axes)

(5,2)  just add

5 - 3 = 2

2 + 2 = 4

Answer :

(2,4)

8 0
3 years ago
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