I can’t understand the question can you write it more clearly?
X= 50
Replace the x with the given number.
Y= 50-20
Y= 30
The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
True:
1) F(x) is read as "F of x".
3) F is the graph at a particular value of x.
5) y is equal to F(x).
1) F(x) is read as "F of x", then first is true.
2) F(x) is the vertical distance on the graph, then second is false.
3) F is the grap at a particular value of x, then third is true.
4) F(x) can be any real number, then fourth is false.
5) y is equal to F(x), then fifth is true.
