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ddd [48]
3 years ago
6

Is PA congruent to PC

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0

Answer: IDK, where's da image?????

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Jerold takes out a 60-month loan for $21,500. At a 1% interest rate, what is his monthly payment?
guajiro [1.7K]

Answer:

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Step-by-step explanation:

7 0
3 years ago
PLEASE HELP ASAP: TRIGONOMETRY
ratelena [41]

Recall that sine is the ratio of opposite over hypotenuse, so we say

sin(theta) = opposite/hypotenuse

If we have a triangle labeled as such in the diagram below, then we can use symbols to write sin(theta) = A/C

Similarly, cos(theta) = B/C since cosine is the ratio of adjacent over hypotenuse.

Then from here we use a bit of algebra to compute the left hand side of the given equation. The goal is to see if we can simplify it to 1.

\sin^2\left(\theta\right)+\cos^2\left(\theta\right)\\\\\left(\sin\left(\theta\right)\right)^2+\left(\cos\left(\theta\right)\right)^2\\\\\left(\frac{A}{C}\right)^2+\left(\frac{B}{C}\right)^2\\\\\frac{A^2}{C^2}+\frac{B^2}{C^2}\\\\\frac{A^2+B^2}{C^2}\\\\\frac{C^2}{C^2}\\\\1

So this shows that the left hand side is identically the same as the right hand side (both sides are 1), and it doesn't matter what you replace theta with. Theta can be any real number and the equation will always be true.

Note: if you're wondering how A^2+B^2 became C^2, it's because of the pythagorean theorem. So that's why this trig identity is often referred to as the pythagorean trig identity.

6 0
3 years ago
(04.04 MC) Are the two triangles below similar? Triangles TUV and WXY are shown. Angle U measures 80 degrees, angle V measures 5
Bingel [31]

Answer:

did u get the answer

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The perimeter of the square is 1 foot how many inches long is each sad
SpyIntel [72]
Im gonna asume you mean side, so 1 foot = 12 inches (: 
3 0
3 years ago
Read 2 more answers
What’s the circumference?
Sliva [168]

Answer:

all the stuff written there are answers if I'm wrong tell me I'll try it out again have a good day.

7 0
3 years ago
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