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3 years ago

HELP how to do this I will give Brainliest

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1 answer:

Makovka662 [10]3 years ago

4 0

Answer:

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1/2ac2 where a =5 and b=2

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I’ll assume the c is b. (1/2) x (5) x (2) x (2) is 10

8 0

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66 is the answer
....

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3 years ago

3 years ago a father was 3 times as old as his son, in five years time he will be twice as old as his son, what will be the sum

ivolga24 [154]

Answer: 46 years

Step-by-step explanation:

Let the father's age be x and the son's age be y, then 3 years ago:

Father = x - 3

son = y - 3

Then , from the first statement :

x - 3 = 3 ( y - 3 )

x - 3 = 3y - 9

x = 3y - 9 + 3

x = 3y - 6 .......................................... equation 1

In five years time

father = x + 5

son = y + 5

Then , from the second statement

x + 5 = 2 ( y + 5 )

x + 5 = 2y + 10

x = 2y + 10 - 5

x = 2y + 5 ........................ equation 2

Equating equation 1 and 2 , we have

3y -6 = 2y + 5

add 6 to both sides

3y = 2y + 5 + 6

subtract 2y from both sides

3y - 2y = 11

y = 11

substitute y = 11 into equation 1 to find the value of x

x = 3y - 6

x = 3(11) - 6

x = 33 - 6

x = 27

This means that the father is presently 27 years and the son is presently 11 years.

In four years time

father = 27 + 4 = 31

son = 11 + 4 = 15

sum of their ages in four years time will be

31 + 15 = 46 years

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671

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8 0

3 years ago