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3 years ago

I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?

Mathematics

2 answers:

Bad White [126]3 years ago

5 0

The number that you are is...
492,630

vladimir1956 [14]3 years ago

5 0

482163 and that’s your answer

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(I WILL RATE BRAINIEST)

Umnica [9.8K]

Answer:

(a)

Shortest Side of the trapezoid =6 yds

Longest Side =8 yds

(b)42 Square Yards

Step-by-step explanation:

Part A

In the Trapezoid, Width =6 yd

Since the shortest side of the playground and its width have the same dimension, then:

Shortest Side of the trapezoid =6 yd

Longest Side =6+1+1=8 yd

Part B

Area of the Playground

In the trapezoid

a=6 yd, b=8 yd, h=Width=6 yd

Area of a trapezoid $=\frac{1}{2}(a+b)h$

$Therefore: Area=\frac{1}{2}(6+8)*6\\=14*3\\=42$ Square Yards$

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3 years ago

AEFG is located at E (0,0), F (-7, 4), and G (0,8). Which statement correctly classifies AEFG?

viva [34]

Answer:

ΔEFG is an isosceles triangle

Step-by-step explanation:

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3 years ago

Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. How many different groups

irakobra [83]

Answer:

56 groups of 5 Fabergé eggs can be taken.

Step-by-step explanation:

It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:

$8C_{5}=\frac{8!}{5!(8-5)!}$

$8C_{5}=\frac{8!}{5!3!}$

$8C_{5}=\frac{8{\times}7{\times}6{\times}5!}{5!{\times}3{\times}2}$

$8C_{5}=56$

Thus, 56 groups of 5 Fabergé eggs can be taken.

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3 years ago

Tom and Sam shared equally one third of a chocolate bar. What fraction of the chocolate bar did each child get?

Savatey [412]

1/3 each , hope it helps

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3 years ago

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The two polygons are similar. Find the values of x and y. Please help, i will mark brainliest

9966 [12]

Do you have a photo?

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3 years ago