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2 years ago

Eight times the sum of 8 and some number is 17. What is the number?

Mathematics

2 answers:

astraxan [27]2 years ago

5 0

8(8+x) = 17
64 + 8x = 16
- 64    - 64
----------------------
   8x = -48
------ ------
   8 8

x = -6

OverLord2011 [107]2 years ago

4 0

Edited answer: The number is: "- 6" .
_______________________________________________

8 (8 + x) = 16 ;

in which "x" represents the number for which to be solved ;

8*8 + 8*x = 16 .

Edit: 64 + 8x = 16 ;

Subtract "64" from each side of the equation:

Edit: 64 + 8x − 64 = 16 <span>− 64 ;

to get: 8x = </span>- 48 ;

Divide EACH SIDE of the equation by "8" ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ;

Edit: 8x / 8 = -48 / 8 ;

Edit: x = - 6 .
______________________________________________
The number is: "- 6" .
______________________________________________
Let us check our answer, by plugging in "-6" for "x" in the original equation:
______________________________________________
8 (8 + x) = 16 ;

→ 8 [8 + (-6) ] =? 16 ?? ;

→ 8 (8 − 6 ) =? 16 ?? ;

→ 8 (2) =? 16 ?? ;

→ 16 = ? 16 ?? Yes!
_________________________________________________

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The area of a rectangular mirror is 15 7 16 square feet. The width of the mirror is 3 1 4 feet. If there is a 5 foot tall space

Vlad1618 [11]

Given:

Area of rectangle = $15\dfrac{7}{16}$ sq. feet.

Width of the mirror = $3\dfrac{1}{4}$ feet.

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Whether it will fit on the wall whose length is 5 foot.

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$\dfrac{Area}{width}=length$

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2 years ago

2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

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