Answer:
Its value is 10.
Step-by-step explanation:
Use order of operations, PEMDAS.
The parentheses are worked out first:-
(5 - 3) X 2 + 6
= 2 X 2 + 6
Now the multiplication:-
= 4 + 6
= 10 (answer).
Answer:
x = 19/2 or 9.5
Step-by-step explanation:
Hello!
We can distribute the parenthesis and solve.
<h3>Solve</h3>
- 2(4x - 3) = 5(2x - 5)
- 2(4x) - 2(3) = 5(2x) - 5(5)
- 8x - 6 = 10x - 25
Move all x terms to one side and integer terms to the other
- 8x - 6 = 10x - 25
- -6 + 25 = 10x - 8x
- 19 = 2x
- x = 19/2
- x = 9.5
-1*/x+3y=12
<span>-4x+3y=-3
-x-3y= -12
-4x+3y= -3
+-------------------
-5x= -15
x=3
</span><span>x+3y=12
</span><span>
3+3y=12
3y=9 y=3
(x,y)=(3,3)</span>
Answer:
cyl=176
Step-by-step explanation:
Answer:
The expected total amount of time in minutes the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of a normal variable:
For the sum of a sample of n values, the mean is of
and the standard deviation is of 
Average 2.8 minutes
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day?

The expected total amount of time in minutes the operator will spend on the calls each day is of 210 minutes.