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3 years ago

Why didn’t the Shah get his own temple?

Mathematics

2 answers:

zmey [24]3 years ago

8 0

The answer to your question is (C)

mamaluj [8]3 years ago

7 0

I think its B I`m not sure

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Define the proper and improper subsets?

Lana71 [14]

Answer: A proper subset is one that contains few elements of the original set whereas an improper subset, contains every element of the original set along with the null set.

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3 years ago

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What is 2x2 equal because I need help

zheka24 [161]

Answer:

Step-by-step explanation:

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4 years ago

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Deanna orders a data set from least to greatest. Complete the sentence by selecting the correct word from each drop-down menu. T

blagie [28]

Hey There!!!!

The Answer Is > Spread and Range I just took the test!

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4 years ago

this is the call plan for minna's cell phone $15 a month plus $0.20 per minute of call time. Minna made 30 minutes of calls this

Ainat [17]

Answer:

To solve this you would do the following:

We know her plan is $15/monthly, regardless of any additional texts/calls she makes.

If 1 minute = $.20 worth of money, we would simply multiply 30 (she made 30 minutes worth of calls) x $.20 ($.20 for each minute). The product is $6.

So, $15 + $6 = $21.

Unless the amount owed per text is mentioned and you forgot to include it in the title, you would not need to take this into consideration.

6 0

4 years ago

In need of some help! Thank you in advance. 100 points <3

Anni [7]

Answer:

the equation (x-4)^2-17=8 has two solutions because it is in a quadratic form.

(x-4)^2-17=8

x²-8x+16-17-8=0

x²-8x-9=0

Doing middle term factorization

x²-9x+x-9=0

x(x-9)+1(x-9)=0

(x-9)(x+1)=0

either

x=9

x=9or

x=9orx=-1

x^2+4x+3=0:

Doing middle term factorization

x²+3x+x+3=0

x(x+3)+1(x+3)=0

(x+3)(x+1)=0

either

x=-3

x=-1

Josh’s solution is incorrect because he missed x=-3.

3.

x^2-6x+7=0

By using quadratic equation formula:

Comparing above equation with ax²+bx+c=0

we get

a=1

b=-6

c=7

Now

we have

x= $\frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

x= $\frac{ 6± \sqrt{ {-6}^{2} - 4*1*7} }{2}$

x= $\frac{ 6±2\sqrt{ 2}}{2}$

x= ${ 3±\sqrt{ 2}}$

Taking positive

x= ${ 3+\sqrt{ 2}}$

taking negative

x= ${ 3-\sqrt{ 2}}$

4 0

3 years ago