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Ratling [72]
2 years ago
12

Why didn’t the Shah get his own temple?

Mathematics
2 answers:
zmey [24]2 years ago
8 0
The answer to your question is (C)
mamaluj [8]2 years ago
7 0
I think its B I`m not sure
You might be interested in
Please could I have some help :)
nirvana33 [79]

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

b.

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

5 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP
Vlada [557]

Answer:

c

Step-by-step explanation:

For an inverse function you take f(x) and turn that to y then you switch x and y. So you should start off with y= 5x -8. so then you switch x and y so x= 5y - 8. So then you solve. You subtract 8 from both sides and divide by 5 and you get F(x) inverse = x + 8/5

8 0
3 years ago
Tay recorded the number of imported cars that drove by his house during rush hour. He collected data for 5 working days. Taye’s
SCORPION-xisa [38]

Answer: D

Step-by-step explanation:

because

4 0
3 years ago
Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)
timama [110]
<h3>Answer:   c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\

With a = -5 and b = 4, we have

f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\

So,

f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\

Use algebra to solve for c

-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\

6 0
2 years ago
PLEASE HELP ASAP &lt;3 Express as a trinomial (3x+5) (x+1) :)
Gennadij [26K]

Answer:

3x^2+8x+5

Step-by-step explanation:

(3x+5)(x+1)

3x(x+1)+5(x+1)        Distribute

3x(x+1)+5(x+1)        Distribute 3x(x+1)

3x^2+3x+5(x+1)        

3x^{2} +3x+5(x+1)         Distrbute 5(x+1)

3x^2+3x+5x+5            Combine like terms

3x^{2} +8x+5

3 0
2 years ago
Read 2 more answers
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