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nexus9112 [7]
3 years ago
10

WILL MARK BRAINLIEST!! NEED ANSWER FAST PLEASE!!!!

Mathematics
1 answer:
slega [8]3 years ago
6 0

Answer:

positive,linear association

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Solving and graphing linear equations practice Y=x+2
grin007 [14]
X=2
Y=4
There are more than 1 solution
4 0
4 years ago
Which one of the following numbers will appear farthest to the right on a number line?
Feliz [49]
\pi is the largest number out of the choices so it will appear furthest to the right of a number line.
5 0
3 years ago
Read 2 more answers
Question 11 of 11 -
alex41 [277]

Answer:

AA similarity

Step-by-step explanation:

Your question is not well presented.

See attachment

Given

Triangles ABC and DBE

Required

Which postulate supports the similarities of ABC and DBE

At the first transformation (180 degrees rotation) both triangles maintain SSS and AAA relationships. i.e <em>Side-Side-Side</em> and <em>Angle-Angle-Angle</em>

This is so because rotations do not alter the side lengths; neither does it alter the angles.

When the second transformation (dilation) takes place, the lengths of both triangles ABC and DBE become different because dilation alters side lengths.

However, angle measurements remain unaltered.

<em>Hence, AAA similarity answers the question</em>

6 0
3 years ago
1) A furlong is 1/8 of a mile. What part of a mile is 6 furlongs?
Semmy [17]

Answer:

6/8 of a mile,

Step-by-step explanation:

if one furlong is 1/8 of a mile, the 6 shall be 1/8 added to itself 6 times, therefore it shall be 6/8.

5 0
3 years ago
Read 2 more answers
In a sample of 88 adults selected randomly from one town, it is found that 6 of them have been exposed to a particular strain of
Ivan
<h2>Answer with explanation:</h2>

Let p be the proportion of of all adults in the town that have been exposed to this strain of the flue .

As per given , we have

H_0:p=0.08\\\\ H_a: p\neq0.08

∵ H_a is two-tailed , so the test is a two-tailed test.

Test statistic :

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

, where p= population proportion

{\hat{p} = sample proportion

n= sample size

Put n= 6 and {\hat{p}=\dfrac{6}{88}\approx0.068  and p=0.08

z=\dfrac{0.068-0.08}{\sqrt{\dfrac{0.08(1-0.08)}{88}}}

z=\dfrac{-0.012}{0.0289199522192}\approx-0.415

P-value for two-tailed test : 2P(Z>|z|)

=2P(Z>|-0.415|)

=2P(Z>0.415)

=2[1-P(Z≤0.415)]   [∵ P(Z>z)=1-P(Z≤z)]

=2(1-0.6609)   [ by z-table]

=0.6782

Decision : Since the p-value(0.6782) is > significance level(0.01) , so we fail to reject the null hypothesis.

We conclude that that we do not have sufficient evidence to support the claim that the proportion of all adults in the town that have been exposed to this strain of the flue differs from the nationwide percentage of 8%.

8 0
3 years ago
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