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3 years ago

I don’t understand this

Mathematics

1 answer:

loris [4]3 years ago

3 0

Answer:

62°

Step-by-step explanation:

The vertex angle is half the difference of the intercepted arc angles.

∠A = ½ (CE − BD)

x = ½ (4x − 10 − 26)

x = ½ (4x − 36)

x = 2x − 18

18 = x

Therefore, the measure of CE is:

4(18) − 10 = 62

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The graph of g(x)=ax^2 opens downward and is narrower than the graph of f(x)=x^2. Which of the

Masteriza [31]

You’re answer is

b

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A moving company charges $40 plus $0.25 per mile to rent a van. Another company charges $25 plus $0.35 per mile to rent the same

Bond [772]

<h3>Answer:</h3>

c. 150 miles

<h3>Step-by-step explanation:</h3>

You want to find the number of miles (m) that make the charges equal.

... 40 +0.25m = 25 + 0.35m

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3 years ago

How many solutions does the equation have 4x + 3=2(2x +9)

lbvjy [14]

I guess no solution
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6 0

3 years ago

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

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3 years ago

Solving the Simplified Equation

Artist 52 [7]

Answer:

- 1.5

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put two x variables in one place and two numbers in one place

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x=-1.5

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3 years ago