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Romashka-Z-Leto [24]
3 years ago
9

If the value of b is 7 , then what is the value of the expression -3b2 + 25 = ?

Mathematics
1 answer:
Katarina [22]3 years ago
6 0
Hello there!

Evaluate
-3b² + 25
For b = 7
-3(7)² + 25
-3(49) + 25
-147 + 25
= -122

I hope that helps!
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Find the lateral area for the pyramid with the equilateral base.
Dafna11 [192]

Answer:

Option A is the correct answer.

Explanation:

 The given pyramid has 3 lateral triangular side as shown below.

 Base of triangle = 12 unit

 We need to find perpendicular.

  By Pythagoras theorem we have

            Perpendicular² = 10²-6²

           Perpendicular = 8 unit

So area of 1 lateral triangle = 1/2 x Base x Perpendicular.

                                             = 1/2 x 12 x 8 = 48 unit²

Area of lateral side = 3 x 48 = 144 unit²    

Option A is the correct answer.                

7 0
3 years ago
Read 2 more answers
The volume of a cube is 441cm3.<br> Work out the length of its side rounded to 1 DP.
Klio2033 [76]

Answer:

volume of a cube = 441cm3.

l³=441cm³

l=7.6cm

5 0
3 years ago
3(2/3) of 4 ÷ 2(1/4) + 2/6 - 1/2​
Ulleksa [173]
It’s the solution for this question
4 0
3 years ago
Simplify the expression completely.
ludmilkaskok [199]

Answer:

- 64s^33/ 9r^37

Step-by-step explanation:

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3 0
2 years ago
(−4 + 5) − (6 + 7) = x x 0
weeeeeb [17]

1

Add the numbers

(

−

4

+

5

)

−

(

6

+

7

)

=

0

({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}

(−4+5)−(6+7)=xx0

(

1

)

−

(

6

+

7

)

=

0

({\color{#c92786}{1}})-(6+7)=xx^{0}

(1)−(6+7)=xx0

2

Add the numbers

1

−

(

6

+

7

)

=

0

1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

1−(6+7)=xx0

1

−

(

1

3

)

=

0

1-({\color{#c92786}{13}})=xx^{0}

1−(13)=xx0

3

Multiply the numbers

1

−

1

⋅

1

3

=

0

1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

−

1

3

=

0

1{\color{#c92786}{-13}}=xx^{0}

1−13=xx0

4

Subtract the numbers

1

−

1

3

=

0

{\color{#c92786}{1-13}}=xx^{0}

1−13=xx0

−

1

2

=

0

{\color{#c92786}{-12}}=xx^{0}

−12=xx0

5

Combine exponents

−

1

2

=

0

-12={\color{#c92786}{xx^{0}}}

−12=xx0

−

1

2

=

1

-12={\color{#c92786}{x^{1}}}

−12=x1

Show less

Solution

−

1

2

=

1

3 0
3 years ago
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