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Gekata [30.6K]
3 years ago
9

HELPPP

Mathematics
2 answers:
alina1380 [7]3 years ago
6 0
Ok, So:

10x3=30-3=27

It Would Be 27
Irina-Kira [14]3 years ago
3 0

Answer:

(x × 3) -3

Step-by-step explanation:


You might be interested in
Which is the correct way to check your answer for -20d=40?
Helen [10]

Answer:

D

Step-by-step explanation:

After you get the answer then you should feel in the d with the number. Example:

-20D=40

Divide both sides by -20

D=-2

So know you should fill in d

-20(-2)=40

40=40

True

4 0
3 years ago
Look at this graph.
Shtirlitz [24]

Answer:

It's exponential

Step-by-step explanation:

5 0
3 years ago
X+y+z=2<br> -x+3y+2z=8<br> 4x+y=4
olga nikolaevna [1]

Answer:

So what do you need help in plz

6 0
3 years ago
Determine if the data comes from a linear function or an exponential function. Then, enter
svet-max [94.6K]

1.  The data is not linear.  There's not a constant difference between the f(x) values.  (AKA there's not a fixed slope between the data points)

2. The data is exponential, because there's a consistent ratio in the f(x) values:

     189/567 = 1/3

     63/189 = 1/3

     21/63 = 1/3

     7/21 = 1/3

Each new y-value (aka f(x)-value) is 1/3 the previous value.

Also, f(0)=567.

If we put that together, we have f(x) = 567 (1/3)^x.

8 0
3 years ago
N(t) = 25t + 150 for 0&lt;=t&lt;6, (200 + 80t)/(2 + 0.05t) for t&gt;=8
nadezda [96]

Answer:

1600. This is a maximum limit of fish the pond can host.

Step-by-step explanation:

For \lim_{t \to \infty} N(t), we must take the part of this function valid for high values, i.e., the second part, where t \geq 8\\.

\lim_{t \to \infty} N(t)=\lim_{t \to \infty} \frac{200+80t}{2+0.05t}

Since we have two polynoms both in numerator and denominator, and both of them are of degree 1 (both linear), for high values of t, the main part of each polynom shall be the linear part, neglecting lower degree parts (in this case, constant terms):

\lim_{t \to \infty} \frac{200+80t}{2+0.05t}=\lim_{t \to \infty} \frac{80t}{0.05t}=\frac{80}{0.05} = 1600

This means that the number of fish in a pond has an <em>horizontal asymthote</em>. In other words, there seems to be a natural limit for the number of fish that there will be in the pond as years pass. The maximum number of fish is actually 1600. With this function, no higher than this figure can be reached. This might imply <em>limits in productivity</em>.

4 0
3 years ago
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