Answer:
area of each triangular base = 24
area of bottom rectangular face = 160
area of back rectangular face = 120
area of sloped rectangular face = 200
Total = 504
Step-by-step explanation:
Answer:B: 36°
Step-by-step explanation:
We know that ∆ABC is isoceles, making (angle)<ABC and <BCA congruent because base angles of isoceles triangles are congruent.
Because we have parallel lines, we can look for alternate interior angle pairs. <BCA is congruent to <DAC because they're alternate interior angles.
If <BCA is x then so is <ABC.
Since triangles add up to 180° we can add all of the angles (3x+x+x) and set it equal to 180.
3x+x+x=180
5x=180
x=36
If we were looking for <BAC we would plug that back in and solve, but we're looking for <BCA which is equal to x, therefore m<BCA=36°
Answer:

Step-by-step explanation:
Given
Geometry Progression


Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP

For first term: Tn = 500 and n = 1




For fought term: Tn = 32 and n = 4


Substitute 500 for a

Make r^3 the subject


Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)

Using: 
and 




<em>Hence, the second term is 200</em>