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3 years ago

HELPPP

Mathematics

2 answers:

alina1380 [7]3 years ago

6 0

Ok, So:

10x3=30-3=27

It Would Be 27

Irina-Kira [14]3 years ago

3 0

Answer:

(x × 3) -3

Step-by-step explanation:

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Find the 98th term of the arithmetic sequence 8, 24, 40,...

Annette [7]

Answer:

Step-by-step explanation:

AP = 8, 24 , 40....

a = 8 , d =16 , n =98 , An = ?

an= a +(n-1)d

an = 8+97*16

an=8+1552

an=1560

hope it helps you..

4 0

3 years ago

Need help on this ASAP!!!!

mestny [16]

The answer is D. He divided both sides by 5 instead of dividing both sides by -5.

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3 years ago

Juan works at bob’s appliance store . he earns $400 per week he also receives a commission of $50 for each appliance he sels

sweet-ann [11.9K]

Answer:

400×W+50×A=?

Step-by-step explanation:

since it's 400 a week then you need to take into account the weeks worked. Then since it's 50 per an appliance you need to multiply by the number sold.

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3 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

In the talent show, 6 students plan to sing, 7 students plan to dance, and 2 students plan to

kumpel [21]

Answer:

Rick is correct

Step-by-step explanation:

7 0

3 years ago

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