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3 years ago

5

If I get on at the bottom of the ferris wheel, in how many degrees will it take for my car to get to the top of the ferris wheel

?

2 answers:

Ne4ueva [31]3 years ago

7 0

Since a ferries wheel goes 360 and let's say the bottoms is 0 then it would be 180 degrees since 180 is half of 360

Keith_Richards [23]3 years ago

5 0

It would take 180* to get to the top.

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74 tens is = < or > than 700+4

Paraphin [41]

>, 74 tens (740)>704

7 0

3 years ago

Read 2 more answers

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago

A quadrilateral with only one pair of parallel sides is called a

shusha [124]

Its called a Rhombus

8 0

3 years ago

Bir araç 5 saatte 80km yol almaktadır. Buna göre bu aracın hızı kaç m/dk'dır?

8090 [49]

80 km = 80000 m
5 saatte = 300 dk’dir
80000m/300 dk’dir = 266.666667 m/dk’dir
(Yazım yanlışsa kusura bakmayın türkçe bilmiyorum :) )

6 0

3 years ago

Plz help me :^(( tyy

Whitepunk [10]

Plug in 1 for x
f(1) = |1-3| + 7
|1-3| = |-2| = 2
f(1) = 2 + 7
Solution: f(1) = 9

5 0

3 years ago