What 9x9=. Ggghuujnnjjkmmmkkkmnnhu

Mathematics

2 answers:

svlad2 [7]3 years ago

5 0

The answer to 9x9 is 81

Alexxandr [17]3 years ago

4 0

9 x 9 is 81 hehehhehe

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The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two

wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean = $\lambda=2$ errors per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

Now, the probability that a randomly selected page does not need to be retyped is given by :-

$P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767$

Hence, the required probability :- 0.6767

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4 years ago

Charlene is knitting a baby blanket. She wants its width, w, to be at least half its length, l. She estimates that she has enoug

zepelin [54]

Answer:

W > 0.5L

Perimeter:

2L + 2W < 180

2L + 2(0.5L) < 180

2L + 1L < 180

3L < 180

÷3 ÷3

L < 60

Length should be less than or equal to 60 inches while width should be greater than or equal to 30 inches.

4 0

3 years ago

Read 2 more answers

The probability that a household owns a pet is 0. 55. Suppose there are 5 houses on a block. Assuming each household is independ

Alexandra [31]

If the probability that a household owns a pet is 0.55 then the probability that all households will have pets is equal to 0.0503.

Given that the probability that a household owns a pet is 0.55 and there are 5 houses on a block.

We are required to calculate the probability that all the five households will have pets.

Probability is basicallly the chance of happening an event among all the events possible. It cannot be negative.

Binomial probability distribution is basically the probability calculations but in different combinations.

In this we have to calculate the probability that all the houses will have the pets then the probability that all five households will have pets is equal to $5C_{5}(0.55)^{5} (1-0.55)^{0}$