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S_A_V [24]
3 years ago
5

You discover that the underlying cause of a disease is a protein that is less stable than the non-disease-causing version of the

protein. this change is most likely to be due to ________.
Biology
1 answer:
GrogVix [38]3 years ago
8 0
<span>You discover that the underlying cause of a disease is a protein that is less stable than the non-disease-causing version of the protein. this change is most likely to be due to </span>
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Which hypothetical scenario would result in
Finger [1]

Answer:

the different phases of the moon are proof that it revolves around the earth at the rate it does, so if it revolved around earth much more slowly, then the phases wouldn't be visible because the sun wouldn't hit the moon as it does now

Explanation:

i don't know why this is being taught who cares about the moon

3 0
3 years ago
What is the significance of sporopollenin in bryophytes
sweet [91]
<span> it's a component of the outer walls of spores and pollen grains, and Bryophytes are mosses, so... I would assume that it's something that protects moss spores.</span>
3 0
3 years ago
You are following segregation of five unlinked genes in a cross – A, B, C, D and E. Dominant alleles are capital letters and rec
bija089 [108]

Answer:

1/64 = 0.015625

Explanation:

Genotype of parents:  aa bb Cc Dd Ee x aa Bb Cc dd Ee

To calculate the frequency of the child with desired genotype, individual frequency of desired genotype can be calculated followed by application of product rule.

aa x aa = All aa

bb x Bb= 1/2 bb: 1/2 Bb

Cc x Cc= 1/4 CC: 1/2 Cc : 1/4 cc

Dd x dd = 1/2 Dd: 1/2 dd

Ee x Ee= 1/4 EE: 1/2 Ee: 1/4 ee

Expected frequency of the child with desired genotype= 1 aa x 1/2 bb x 1/4 cc x 1/2 dd x 1/4 ee = 1/2 x 1/4 x 1/2 x 1/4 = 1/64 = 0.015625

6 0
3 years ago
A litter of mice from the mating of two agouti black parents includes offspring with the following fur colors:
Anika [276]

Answer:

<h2>3/16 </h2>

Explanation:

Given:

Parents are;

both parents are Agouti black and agouti black ( AaBb);

Black is dominant on brown (B over b);

Agouti is dominant on solid color ( A over a);

So, progeny are  

(AABB, AaBb, AABb, AaBB, Aabb, aaBB, aaBb aabb  so on )

Here 3 out of 16 progeny are agouti brown ( genotype AAbb, Aabb);

So,expected frequency of agouti brown offspring in the litter= 3/16.

8 0
3 years ago
Read 2 more answers
Order the events in which telomerase maintains chromosomal ends during replication. not all events will be placed.
inn [45]
<span>The RNA in telomerase is binded to a complementary sequence on DNA specifically to 3' G overhang and also the Nucleotides associated to RNA component of telomerase are binded to DNA at the 3 end. Now the Telomerase moves through DNA strand that is newly synthesized towards the 3 end. In the same way if there are any additional nucleotides they were all binded to 3 end of the DNA and then the telomerase is removed from the DNA completely. now to fill in the gap left by telomerase the synthesis occurs on the 5 end of DNA strand.</span>
5 0
3 years ago
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