Answer: something that deviates normal
Explanation: I know because I study anomaly
The correct answer is that a bacteriophage lambda chromosome containing the human collagen gene, because Recombinant DNA is the name given to DNA molecules that have part of DNA derived from two or more sources, usually these sources are different species. Recombinant DNA technology is also known as molecular cloning or even gene cloning.
B. A bacteriophage lambda chromosome containing the human collagen gene
<h3>How is recombinant DNA produced?</h3>
Obtaining recombinant DNA is based on the molecular cloning technique. The process can be summarized as follows:
- The first step is to isolate a DNA fragment, which contains the gene of interest. Remember that each gene makes a protein.
- The gene of interest, now isolated, is placed in a medium with a fragment of circular bacterial DNA, the plasmid and the restriction enzymes.
- The bacterial plasmid has the ability to insert a fragment of DNA external to its own genome.
<h3>What is DNA and what is it for?</h3>
DNA is the structure responsible for the transmission of all genetic characteristics — such as eye, skin and hair color, physiognomy, among others — in the process of reproduction of living beings. Thus, the main function of DNA is to transport information contained in its sequences, called genes.
Learn more about DNA in brainly.com/question/264225
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Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
