Find the equation of the line that is perpendicular to x - y = -5 and passes through (4, 7).

1 answer:

8 0

X - y = -5
-y = -x - 5
y = x + 5...slope here is 1. A perpendicular line will have a negative reciprocal slope. All that means is flip ur slope and change the sign. So our perpendicular line will have a slope of -1.

y = mx + b
slope(m) = -1
(4,7)...x = 4 and y = 7
now we sub and find b, the y int
7 = -1(4) + b
7 = -4 + b
7 + 4 = b
11 = b

so ur perpendicular equation is : y = -x + 11 <==

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Pavel [41]

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(2-7m^6)^2

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(-7m^6 + 2)^2

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(-7m^6 + 2)(-7m^6 + 2)

-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)

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-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)

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solution:

49m^12 - 28m^6 + 4

please mark brainliest and hope it helps

7 0

3 years ago

Suppose that the cost of producing n pairs of shoes is given by the expression c(n)=30+5n. the average cost of producing a pair

makkiz [27]

<h3>Given</h3>

$c(n)=30+5n\\a(n)=\dfrac{c(n)}{n}$

$\dfrac{d}{dn}(a(n))\quad\text{at n=10}$

<h3>Solution</h3>

$\dfrac{d}{dn}(a(n))=\dfrac{d}{dn}\left(\dfrac{30+5n}{n}\right)=\dfrac{d}{dn}\left(30n^{-1}+5\right)\\\\=-30n^{-2}\\\\=-30\cdot 10^{-2}\qquad\text{at n=10}\\\\=-0.30$