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3 years ago

Please help me Show your work 11 points

Mathematics

2 answers:

AlekseyPX3 years ago

7 0

Since the ratio of the sides of ABC to PQR is 4:6, the ratio of the areas of ABC to PQR is 16:36.

So 40cm2 * 36/16 = 90cm2.

ozzi3 years ago

5 0

Answer:

The area of ΔPQR = 90 cm²

Step-by-step explanation:

Points to remember

If two triangles are similar, then ratio of their areas is equal to square of ratio of their corresponding sides.

It is given that,

ΔABC ~ ΔPQR

<B = < Q

<C = <R

ar(ΔPQRC) = 40 cm²

To find the area of ΔPQR

We have ,

ar(ΔABC)/ar(ΔPQR) = AB/PQ

40/ar(ΔPQR)= (4/6)² = 16/36

ar(ΔPQR) = (36 * 40)/16 = 90 cm²

Therefore area of ΔPQR = 90 cm²

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rjkz [21]

Answer:

$x = -\frac{3}{2}$ or $x = 1$

Step-by-step explanation:

Using the zero product property, first step is to set the given equation, $2x^2 + x - 1 = 2$ , to zero. Then factorise the left side.

Thus,

$2x^2 + x - 1 = 2$

Subtract 2 from both sides

$2x^2 + x - 1 - 2 = 2 - 2$

$2x^2 + x - 3 = 0$

Factorise the left side

$2x^2 + 3x - 2x - 3 = 0$

$x(2x + 3) - 1(2x + 3) = 0$

$(x - 1)(2x + 3) = 0$

Find the solution

$x - 1 = 0$

$2x + 3 = 0$

$x = 1$

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$x = -\frac{3}{2}$

The answer is: $x = 1$ or $x = -\frac{3}{2}$

3 0

3 years ago

The area of a rectangle is 65 m2 , and the length of the rectangle is 3 m less than twice the width. find the dimensions of the

salantis [7]

X = width
2x-3 = length

 $x(2x-3) = 65\\
2x^2 - 3x - 65 = 0 \\ D=b^2-4ac=(-3)^2-4*2*(-65)=529\\
x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{3б 23}{4} \\ x_1=-5 \ \ \O \\ x_2=6.5 \ \$

width = 6.5 m
length = 2x-3 = 2*6.5 - 3 = 10 m

4 0

3 years ago

Help pls ! i’ll mark brainliest to whoever answers it right first. thanks !

Bess [88]

About 90ft

step-by-step explanation: 1/2 (a+b) x h is area of trapezoid. So that would be 40
then area of circle is pi x radius squared. So that is 50.24 roughly.

so 50+40=90

and yeah

hope this helped :))

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3 years ago

Premises: All good students are good readers. Some math students are good students. Conclusion: Some math students are good read

just olya [345]

Answer:

Therefore, the conclusion is valid.

The required diagram is shown below:

Step-by-step explanation:

Consider the provided statement.

Premises: All good students are good readers. Some math students are good students.

Conclusion: Some math students are good readers.

It is given that All good students are good readers, that means all good students are the subset of good readers.

Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.

Therefore, the conclusion is valid.

The required diagram is shown below:

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3 years ago

Stephanie bought 36.5 inches of lumber at Home Depot the lumber cost 2.10 per inch including the sales tax. Stephanie bought 36.

tamaranim1 [39]

Answer:76.65

Step-by-step explanation:

First, you write 36.5 times 2.10

Then, multiply them.

That equals 76.65

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3 years ago