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2 years ago

Is 5/16 needle length smaller than 1/4?

Mathematics

2 answers:

yarga [219]2 years ago

8 0

No they are the same size because if you convert 1/4 into /16 it equals 5/16.

Zina [86]2 years ago

5 0

Answer: nope.

Step-by-step explanation: try converting to a common denominator.

1/4 * 4/4 = 4/16 5/16 = 5/16

Now, the fraction with the bigger numerator would be the larger fraction.

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Billy likes to go cycling.

olganol [36]

130 revolutions is 130×85π=34714.60cm=347.146m or 347m to the nearest metre.

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2 years ago

True or false: Outliers can cause data sets to be skewed.

Natali [406]

True - since the outlier is way off it will cause your average to mess up which is why we test multiple times to make sure we are more accurate with our numbers

4 0

1 year ago

Read 2 more answers

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

$\frac{m^{5} }{162n}$

Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

8 0

3 years ago

Read 2 more answers

Indicate all possible values for the variable in each of the expressions: sqrt(2x+2)+sqrt(6-4x)

IrinaK [193]

Answer:

Given expression:

$\sqrt{2x+2}+\sqrt{6-4x}$

The first root is valid when:

2x + 2 ≥ 0 ⇒ 2x ≥ - 2 ⇒ x ≥ - 1

The second root is valid when:

6 - 4x ≥ 0 ⇒ 4x ≤ 6 ⇒ x ≤ 1.5

So the variable x can get values within interval:

-1 ≤ x ≤ 1.5 or
x = [-1, 1.5]

3 0

2 years ago

Identify the initial amount a and the growth factor b in the exponential function.

alina1380 [7]

Given the equation A (x) = 30 x 8.3 ^x, we can get the initial amount of A when x is equal to zero. Therefore:

A (0) = 30 * 8.3^0

A (0) = 30

In this case the equation grows by 8.3 times as x increases. Therefore the growth factor is 8.3.

Answers:

initial amount = 30

growth factor = 8.3

The answers are not in the given choices. I believe you are giving the wrong equation. If the correct equation here is:

A (x) = 680 x 4.3 ^x

Then the answers are:

initial amount = 680

growth factor = 4.3

The answers are now in the choices given.

7 0

3 years ago