Answer:
The price of the cake is $24 and the price of the Pie is $15
Step-by-step explanation:
Given
<em>Represent price of Cake with C and Price of Pie with P</em>

Cakes sold = 8
Pies sold = 14

Required
Determine C and P
To represent the cakes and pies sold, we have the following expression

Substitute 9 + P for C

Open the bracket

Collect Like Terms


Divide both sides by 22


Recall that



<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>
We known that the figures are similar if and only if the corresponding sides and and angles have the common scale factor. In this item, the scale factor is 0.6. The length of AB is determined by multiplying the length of FG with the scale factor. That is,
AB = FG x scale factor
AB = (12 cm) x 0.6
AB = 7.2 cm
Thus, the length of side AB is 7.2 cm.
The amount that the credit union will finance is $24169.60
We have given that the cost of the car is $22,346. 16
and the credit union required 10% down payment
and sale tax=7.6%
The license and title charges are $125. 13.
We have to determine that the amount that the credit union will
finance Now we have sale tax 7.6% for $22,346. 16
Therefore, we get

<h3>What is the amount that the credit union finance ?</h3>
credit union finance=cost of car+sales tax+the license and title charges.

Therefore, the amount that the credit union will finance is $24169.60
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Answer:
There is enough evidence to support the claim that the population mean is greater than 100
Step-by-step explanation:
<u>Step 1</u>: We state the hypothesis and identify the claim
and
(claim)
<u>Step 2</u>: Calculate the test value.


<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134
<u>Step 4</u>: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).
<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.
<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for
and d.f=39 and compare to the test-value:
The critical value (1.685>1.126) falls in the non-rejection region. See attachment.
NB: The t- distribution must be used because the population standard deviation is not known.
Yes it should bring it up to a C or maybe it will be a 70 or 75