Answer:
![Distance = 39.2](https://tex.z-dn.net/?f=Distance%20%3D%2039.2)
Step-by-step explanation:
Given
![Distance = 6ft;\\ Time = 15seconds](https://tex.z-dn.net/?f=Distance%20%3D%206ft%3B%5C%5C%20Time%20%3D%2015seconds)
Required
Determine the distance covered in 98 seconds
To solve this, the following assumption must be made:
- <em>The peacock walks at a constant speed</em>
So, first we calculate the speed
![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
Substitute 6 for Distance and 15 for Time
![Speed = \frac{6}{15}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7B6%7D%7B15%7D)
![Speed = 0.40](https://tex.z-dn.net/?f=Speed%20%3D%200.40)
Next, is to calculate the required distance
![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
In this case:
because it is constant and
![Time = 98](https://tex.z-dn.net/?f=Time%20%3D%2098)
The expression becomes:
![0.40 = \frac{Distance}{98}](https://tex.z-dn.net/?f=0.40%20%3D%20%5Cfrac%7BDistance%7D%7B98%7D)
Make Distance the subject:
![Distance = 0.40 * 98](https://tex.z-dn.net/?f=Distance%20%3D%200.40%20%2A%2098)
![Distance = 39.2](https://tex.z-dn.net/?f=Distance%20%3D%2039.2)
<em>The peacock will walk 39.2 feet in 98 seconds</em>
Answer:
Step-by-step explanation:
![10c - 3d = 30 \\ 10c = 3d + 30 \\ \huge \purple {\boxed{c = \frac{3d + 30}{10}}} \\](https://tex.z-dn.net/?f=10c%20-%203d%20%3D%2030%20%5C%5C%2010c%20%3D%203d%20%2B%2030%20%5C%5C%20%20%5Chuge%20%5Cpurple%20%7B%5Cboxed%7Bc%20%3D%20%20%5Cfrac%7B3d%20%2B%2030%7D%7B10%7D%7D%7D%20%20%5C%5C%20)