1/5,6/30 tell if it forms a porportion

Help with math question pls!

Lady_Fox [76]

The answer is y to the power of negative 1, I think. Because -4+3 is -1.

3 0

4 years ago

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Evaluate: 13 × 20 – 15 × 9 + 20 × 7 – 6 × 15.

ddd [48]

Answer:

175

Step-by-step explanation:

13 × 20 – 15 × 9 + 20 × 7 – 6 × 15 = 175

5 0

3 years ago

Escape park owner was 30% of each order to include long boards he wants to know how many long boards to order out of a total of

Nataliya [291]

Answer:

He should order 15 long boards

Question:

Escape park owner want 30% of each order to include long boards he wants to know how many long boards to order out of a total of 50 skateboards

Step-by-step explanation:

Let x and y represent the number of long board and the total number of skateboard to order.

Given that 30% of each order to include long boards;

x = 30% of y

x = 0.3y .....1

But, the total number of skateboard is given as 50

y = 50

From equation 1

x = 0.3y = 0.3(50)

x = 15

He should order 15 long boards

7 0

3 years ago

NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

Calculate the answer to the appropriate number of significant figures. (do not convert to scientific notation) 6.47 x 64.5

telo118 [61]

Answer:

$6.47 \times 64.5 \\ = 417.315$

4 0

3 years ago

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