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natta225 [31]
3 years ago
15

What is the distance between -2/3 and 4/3 on a number line?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
If from the negative to the positive side, count how many dots are in between and add together. So it is 6 units apart or 6 dots apart.
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It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele
kow [346]

Answer:

t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974      

p_v =P(t_{99}>8.974)=9.43x10^{-15}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.      

Step-by-step explanation:

1) Data given and notation      

\bar X=23500 represent the sample mean  

s=3900 represent the sample standard deviation      

n=100 sample size      

\mu_o =2000 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:      

Null hypothesis:\mu \leq 2000      

Alternative hypothesis:\mu > 2000      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974      

Calculate the P-value      

First we need to calculate the degrees of freedom given by:  

df=n-1=100-1=99  

Since is a one-side upper test the p value would be:      

p_v =P(t_{99}>8.974)=9.43x10^{-15}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.      

8 0
3 years ago
Miyuki can type 135 words in 3 minutes.How many words can she expect to type in 8 minutes?
Alekssandra [29.7K]
135 / 3 is 45 and 45 x 8 is 360 so she can type 360 words in 8 minutes.
5 0
3 years ago
Read 2 more answers
A worker can assemble 3 shelf units each hour. During the fifth hour of the shift, there were 115 shelf units in the warehouse.
nasty-shy [4]
A worker can assemble 3 shelf units each hr. During the 5th hr...so the shift has been going on for 5 hrs...at 3 units per hr = (3 * 5) = 15 units assembled during the shift....and if there was 115 units in the warehouse, then that means before the shift, there were (115 - 15) = 100 units assembled <=
4 0
3 years ago
PLEASE HELP<br> ANSWER SERIOUSLY
alex41 [277]

Answer:

raise a product to a power.

you first simplify the parenthesis in the numerator by raising 2 by the power of three and multiplying the exponents.

i suck at explaining, but after the first step the expression looks like:

(\frac{8r^{6}t^{3}  }{4t^{2} })^{2}

Step-by-step explanation:

5 0
3 years ago
Evaluate the following expression:<br>p/-3 + (-8)= -8
aalyn [17]
P/-3+(-8)=-8
p/-3-8=-8
Add 8 to each side
p/-3-8+8=-8+8
p/-3=0
Multiply both side by 3
p/-3(3)=0(3)
p=0
Check:
p/-3+(-8)=-8
Substitute p with 0
0/-3+(-8)=-8
0-8=-8
-8=-8. As a result, p=0. Hope it help!
7 0
3 years ago
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