Answer:
<h3> To find x you need to divide polygon into triangles</h3><h3>The formula
: "the sum of exterior angles=360°" is false for concaved polygons</h3>
Step-by-step explanation:
α = 180° - 135° = 45°
β = 180° - 120° = 60°
γ = 180° - 60° = 120°
δ = 180° - x
ε = 180° - 80° = 100°
If we divide the pentagon into five triangles then:
5•180° = α + β + γ + δ + ε + 4x
900° = 45° + 60° + 120° + x + 100° + 4x
900° = 325° + 5x
5x = 575°
x = 115°
60° + 120° + 135° + 80° + 115° = 510° ≠ 360°
Answer:
(-5,-8)
Step-by-step explanation:
If M(x,y) is the midpoint of the segment CD, where
then

You are given two points A(-2,-3) and B(1,2), let point F be the point with coordinates (x,y). Yuo know, that point A is the midpoint of BF, then

Substitute known coordinates:

So, point F has coordinates (-5,-8)
Answer:
11
Step-by-step explanation:
Let x be the unknown number
2x+5 = 27
Subtract 5 from each side
2x+5-5 = 27-5
2x = 22
Divide each side by 2
2x/2 = 22/2
x = 11
The number is 11
Answer:
B
Step-by-step explanation:
The formula for acceleration is velocity over time, and when solved, 60 divided by 5 is 12.
Hope this helps!
Answer:
The interquartile range (IQR) for town A, 15° is less than the IQR for town B, 20°.
Step-by-step explanation:
From the boxplot Given ;
Town A :
The first quartile, Q1 = 15
Third quartile, Q3 = 30
The interquartile range, IQR = Q3 - Q1 = 30 - 15 = 15°
TOWN B :
The first quartile, Q1 = 20
Third quartile, Q3 = 40
The interquartile range, IQR = Q3 - Q1 = 40 - 20 = 20°
The interquartile range (IQR) for town A, 15° is less than the IQR for town B, 20°.