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3 years ago

Urgent help please! Answer any of the questions!

Mathematics

1 answer:

kiruha [24]3 years ago

8 0

#1. x = - (2y) / (1-y)

#2. x = (-4y-3)/(1-y)

I can't really see the other questions, so I only did the first two. Hope this helps!

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Mr. Lafond is building a rectangular dog run in his backyard. He uses 86 feet of fencing to enclose the dog run. The dog run is

prohojiy [21]

Here,

Perimeter (P)=86 feet

Length (l)=25 feet

Let, width(b)= x feet

Then,

Perimeter= 2(l+b)

86=2(25+x)

43=25+x

x=18

Hence, required width is 18 feet...

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3 years ago

HELP DUE IN 20 MINS!<br><br> x = ??

DerKrebs [107]

$\huge{ \mathcal{ \underline{ Answer} \: \: ✓ }}$

We know,

$27 \times (x + 27) = 36 {}^{2}$

$x + 27 = \dfrac{1296}{27}$

$x + 27 = 48$

$x = 21$

______________________

$\mathrm{ ☠ \: TeeNForeveR \:☠ }$

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3 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

Yoo help a girl out!!! During a snowstorm, Robert tracked the amount of snow on the ground.

nlexa [21]

Answer: Ok, so make a graph on paper. On the vertical line put inches of snow going up by one. Then your horizontal line should be hours. For the first two hours make the line go up steadily by one. Then make your line flat for five hours. Then for another six hours make the line go up by two per hour.

Please mark brainliest.

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3 years ago

eff can paint 28 square feet every 30 minutes. Angela can paint 50 square feet every hour. Who can paint faster, and by how many

lisabon 2012 [21]

Guessing “eff” is Jeff ;)
28 sq feet/30 min = 56 sq feet/60 minutes

Angela
50 sq feet/60 min

So Jeff paints 6 square feet more per hour.

4 0

3 years ago