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3 years ago

Is a strap of leather a pure substance

Chemistry

2 answers:

Olin [163]3 years ago

8 0

No. it's not a pure
substance

Andrew [12]3 years ago

4 0

I'd say no because the only pure substances are elements

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The number of bonded pairs of _______ in a covalent bond equals the bond order.

egoroff_w [7]

The number of bonded pairs of electrons in a covalent bond equals the bond order.

For example:
In molecule of hydrogen (H₂), bond order is 1 (H-H), because there is one pair of electrons between hydrogen atoms.
In molecule of oxygen (O₂), bond order is 2 (O=O), because there are two pair of electrons (4 electrons) between oxygen atoms.
In molecule of nitrogen (N₂), bond order is 3 , because there are three pair of electrons (6 electrons) between nitrogen atoms.

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3 years ago

What is produced during the replacement reaction of Cu(NO3)2 and Zn?

PolarNik [594]

During the displacement reaction , copper (cu) and zinc nitrate ( 2 ZnNo3 ) are the products . hope this helps :)

8 0

3 years ago

How do i find the atomic mass and number ?

grin007 [14]

To get the atomic mass you need to combine the neutrons and protons together, and the atomic number is the number of protons in an atom!

Hope this helps if not comment below please!!!

3 0

2 years ago

25 L of a gas is collected at 115 kPa. If the pressure increases to 300 kPa, what is the new volume?

Lina20 [59]

Answer:

V2 = 9.58 Litres.

Explanation:

Given the following data;

Initial volume = 25 L

Initial pressure = 115 kPa

Final pressure = 300 kPa

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

$PV = K$

$P_{1}V_{1} = P_{2}V_{2}$

Substituting into the equation, we have;

$115 * 25 = 300*V_{2}$

$2875 = 300*V_{2}$

$V_{2} = \frac {2875}{300}$

$V_{2} = 9.58$

V2 = 9.58 L

Therefore, the new volume is 9.58 litres.

5 0

2 years ago

Please help thaank youu

krek1111 [17]

First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
$Co=58.933$
$Cl=35.45$
$H=1.008$
$O=15.999$

Now, let's find the mass of each compound.

$CoCl_2=58.933+2(35.45)=129.833$
$H_2O=2(1.008)+15.999=18.015$

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

$6(18.015)=108.09$
$129.833+108.09=237.923$

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

$\dfrac{108.09}{237.923}$

$\approx0.45431$

Turn that into a percentage and you get 45.431%.
Hope this helps! :)

6 0

3 years ago