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koban [17]
3 years ago
11

When c-14 transmutates into n-14, this represents 14 6 carbon becomes 14 7 nitrogen plus blank an alpha decay electron capture n

egative beta decay gamma decay?
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
7 0
Answer is: <span>negative beta decay.
</span>
Nuclear reaction: ¹⁴C → ¹⁴N + e⁻ + νe (electron antineutrino).
<span>In beta minus decay (atomic number Z is increased by one, from 6 in carbon to 7 in nitrogen) neutron is converted to a proton and an electron and an electron antineutrino.
</span><span>Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.</span>

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Suppose that 2.14 grams of H2SO4 is mixed with enough water to make 225 mL of solution. Determine the Molarity (M) of the soluti
Alik [6]

Answer:

0.0970 M

Explanation:

Remember this equation:

mol/M x V

Convert it so that you can get M.

M=mol/V

Convert the 2.14 grams of H2SO4 into mols

=0.0218

Convert mL to L

225/1000

=0.225

Plug it in.

0.0218/0.225

=0.0970 M

6 0
3 years ago
When a quantity of electricity is converted to heat, what is the heat energy produced measured in
Mnenie [13.5K]
 It is measured in joules
8 0
3 years ago
Read 2 more answers
At standard pressure, ammonia melts at 195 K and boils at 240 K. If a sample of ammonia at standard pressure is cooled from 200
Svetradugi [14.3K]

Answer:

I) the heat capacity of ammonia(s)

II) the heat capacity of ammonia(ℓ)

IV) the enthalpy of fusion of ammonia

Explanation:

Initially, ammonia at 200 K is liquid. To calculate the change of enthalpy from 200 K to 195 K (melting point) we need to know the heat capacity of ammonia(ℓ).

At 195, ammonia is in the transition from liquid to solid (solidification). To calculate the change of enthalpy in that process we need to know the enthalpy of solidification of ammonia, which has the same value but opposite sign to the enthalpy of fusion of ammonia.

From 195 K to 0 K, ammonia is solid. To calculate the change of enthalpy in that process we need to know the heat capacity of ammonia(s).

7 0
3 years ago
HELP PLZ ASAP I NEED IT and no links plz ANd Plz HURRRRRy
mars1129 [50]

<u>Answer:</u> The balanced chemical equation is 2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

<u>Explanation:</u>

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation:

KClO_3(s)\rightarrow KCl(s)+O_2(g)

<u>On the reactant side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 3

<u>On the product side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 2

To balance the equation, we must balance the atoms by adding 2 infront of both KClO_3(s) and KCl(s). Also, a coefficient of 3 must be written infront of O_2(g)

For the balanced chemical equation:

2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

5 0
3 years ago
An unknown amount of Al203 decomposed producing 215 g of solid aluminum. 2Al2O3=4Al+3O2 How many grams of oxygen gas should be p
natulia [17]

Answer:

191.11 grams of oxygen gas should be produced.

Explanation:

The balanced reaction is:

2 Al₂O₃ → 4 Al + 3 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al₂O₃: 2 moles
  • Al: 4 moles
  • O₂: 3 moles

Being the molar mass of each compound:

  • Al₂O₃: 102 g/mole
  • Al: 27 g/mole
  • O₂: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al₂O₃: 2 moles* 102 g/mole= 204 grams
  • Al: 4 moles* 27 g/mole= 108 grams
  • O₂: 3 moles* 32 g/mole= 96 grams

Then you can apply the following rule of three: if by stoichiometry 108 grams of aluminum are produced along with 96 grams of oxygen, 215 grams of aluminum are produced along with how much mass of oxygen?

mass of oxygen=\frac{215 grams of aluminum*96 grams of oxygen}{108grams of aluminum}

mass of oxygen= 191.11 grams

<u><em>191.11 grams of oxygen gas should be produced.</em></u>

6 0
2 years ago
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