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kodGreya [7K]
3 years ago
15

In beta decay, what is emitted? A. an electron B. a helium-4 atom C. a neutron D. a photon E. a radionucleus

Chemistry
2 answers:
myrzilka [38]3 years ago
4 0

Answer: A. an electron

<u>Beta particles are electrons or positrons (electrons with positive electric charge or antielectrons).</u> Beta decay is a type of radioactive decay in which a beta ray is emitted from an atomic nucleus.

<u>Beta decay occurs when, in an unstable nucleus with too many protons or too many neutrons, one of the protons or neutrons transforms into the other.</u> In beta minus decay, a neutron is broken down into a proton, an electron, and an antineutrino (the neutrino antiparticle, meaning it has an opposite charge to the neutrino). In beta decay plus, a prototype breaks down into a neutron, a positron and a neutrino.

Step2247 [10]3 years ago
4 0

Answer:

A an electron

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Nitrogen transmutes to form an isotope of oxygen. The superscript for oxygen is
a_sh-v [17]
₇N¹⁴ + ₂He⁴ → ₈O¹⁷ + ₁H¹

The superscript for oxygen is 17.
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3 years ago
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How many cm are in 7 km?
nikklg [1K]

Answer:

70000 cm in 7km

Explanation:

There are 1000 m and 100 cm in 1 m in 1 km, so to find how many cm are in 7 km you need to do 10000 x 7.  You get 70000

Have a nice day!

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3 years ago
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Enthalpies of reaction calculated from bond energies and from enthalpies of formation are often, but not always, close to each o
jolli1 [7]

The enthalpy change in a reaction is given by-

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

This can be expressed in terms of bond energy as-

ΔH°rxn = BEreactants - BEproducts

Therefore, the calculated bond energy according to the above equation will be-

ΔH°rxn = [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) ] - [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H)  = 0 kJ/mol

<h3>What is enthalpy change?</h3>

Enthalpy change is a measure of the energy emitted or consumed in a reaction. This can be determined using the following equation which involves standard enthalpy of reactant and product formation:

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

<h3>What is bond energy?</h3>

Bond energy is defined as the amount of energy needed to dissociate a mole of molecules into their individual atoms.

Learn more about the Enthalpy Change here:

brainly.com/question/14047927

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6 0
2 years ago
Given the following equation:
Anna [14]

Mass of KMnO4 required : 31.607 g

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

2KMnO₄ → K₂MnO₄ + MnO₂ + O₂

mol of O₂ :

\tt \dfrac{1.6}{16}=0.1

mol ratio KMnO₄ : O₂ = 2 : 1

mol of KMnO₄ :

\tt \dfrac{2}{1}\times 0.1=0.2

mass of KMnO₄ :

MW KMnO₄ : 158,034 g/mol

\tt mass=0.2\times 158,034 =31.607~g

4 0
3 years ago
Measurements show that unknown compound X has the following composition:
zvonat [6]

Answer: The empirical formula of X is C_{5}H_4O_2.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 62.4 g

Mass of H = 4.19 g

Mass of O = 33.2 g

Step 1 : convert given masses into moles.

Moles of C=\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{62.4g}{12g/mole}=5.2moles

Moles of H=\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.19g}{1g/mole}=4.19moles

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{33.2g}{16g/mole}=2.1moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{5.2}{2.1}=2.5

For H =\frac{4.19}{2.1}=2

For O =\frac{2.1}{2.1}=1

The ratio of C: H: O = 2.5 : 2 : 1

Converting it into simple whole number ratios by multiplying by 2:

Hence the empirical formula of X is C_{5}H_4O_2.

6 0
4 years ago
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