Answer:
Step-by-step explanation:
I made a table with a pretend number of years of teaching by picking a somewhat random number to start
"Clark has less seniority than Cornwall but more than Prendergast:" I picked 3 for Clark 4 for Cornwall, and 2 for Prendergast, to start.
"Prendergast has more than Brown but less than Alexander:" I see I'm running out of easy numbers here. "Prendergast has more than Brown" means give Brown 1 year but this new teacher, Alexander needs a number between Clark and Prendergast. To make room, I increased Clark and Cornwall by 1 and finished the remainder in the "Final Years" column:
<u>Teacher </u> <u>Years</u> <u> Final Years</u>
Clark 3 4
Cornwall 4 5
Prendergast 2
Brown 1
Alexander 3
The highest seniority teacher, Cornwall, is smart and refuses the job. That leaves Clark, at number 2 seniority, to become the new supervisor.
Answer:
1.4 × 10^-8
Step-by-step explanation:
The chip is 14 nanometers
14 * .000000001
.000000014
Move the decimal 8 places to the right, because we need 1 number in front of the decimal for scientific notation. The exponent will be -8 because we moved it 8 places to the right
1.4 × 10^-8
31/61 or 50.8 percent
the daily passes added together are 31 passes for adults and children. Adding everything together gives us the denominator of the fraction 61. 31/61 = 50.8%.
From the given figure, we know that:
This means that the three sides of triangle MNO are congruent to three sides of triangle LMO. Therefore, the triangles are congruent by Side Side Side postulate.
Answer:
a) CI = ( 5,1 ; 5,7 )
b) SE = 0,1
Step-by-step explanation:
a) Sample random n = 100
Mean = μ = 5,4
Standard deviation s = 1,3
CI = 99 % α = 1 % α = 0,01 α/2 = 0,005
z(c) for 0,005 is from z-table z(c) = 2,575
z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n
CI = 5,4 ± 2,575* 1,3/10
CI = 5,4 ± 0,334
CI = ( 5,1 ; 5,7 )
b) SE = Standard deviation / √n
SE = 1,3 /10 SE = 0,1
We can support that with 99 % of probability our random variable will be in the CI.
