I would use a confidence interval to estimate the mean fuel savings because of the range of the data. If the data were close together, a simple mean would be enough. Here there is a wide spread of values between 48.3 and 6.9. A confidence interval would be a good representation of the values.
√(1/121) = √1 / √121 = 1 / 11 = <em>11⁻¹</em>
Answer: sec^4(x)-tan^4(x) = 1+2 x tan^2(x)
Step-by-step explanation:
Answer:1 23/28
Step-by-step explanation:
17/3/3 1/9
17/3/28/9
51/28
1 23/28
The "Pre Image" is the image that we started with, so the pink triangle.
The "Image" is the image that we ended with, so the blue triangle.
To determine how far we went from the pre image to the image, we can focus on one point, let's say point "P".
The pre image coordinates for point "P" are 2, 3.
The image coordinates for point "P'" are -1, 0.
To get from x value 2 to x value -3, we subtracted 3.
To get from y value 3 to y value 0, we subtracted 3.
So, our rule for this translation would be A, (x, y) ----> (x-3, y-3).
