All categories

3 years ago

Which statement is false?

1 answer:

4 0

The statement that is false is choice A. On a parallelogram, the diagonals will always be congruent even if it is not a rectangle. To test this, draw numerous parallelograms and draw in the diagonals. They will be the same length even though they are not rectangles.

You might be interested in

help plzzz , ik it’s a test n all but this was from last year n I have to do it for this year n it’s due today :( I’ve been stre

Westkost [7]

Answer:

Step-by-step explanation:

2(x)+4=16

2(6)+4=16

12+4=16

7 0

3 years ago

The common ratio in a geometric series is 0.50.50, point, 5 and the first term is 256256256.

V125BC [204]

Answer:

504

Step-by-step explanation:

I think the correct question is like:The common ratio in a geometric series is 0.50 ( point 5) and the first term is 256.

Find the sum of the first 6 terms in the series.

If it's right, then

Sₙ = (a₁ * (1 - rⁿ)) / (1 - r)

S₆ = (256 * ( 1 - 0.5⁶)) / (1 - 0.5) = (256 * 0.984375) / 0.5 = 504

6 0

2 years ago

Help please?!?!?!?!?!?!

svp [43]

slope is change in y over change in x

use 2 points from the table so -3,-21 and -6,-39

change in Y: -39 - -21 = -18

change in x = -6 - -3 = -3

slope = -18/-3 = 6

slope = 6

8 0

2 years ago

Todea what did one pencil say to another mathematics algebra order of operations answer

Serjik [45]

Part 1

$6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)} \\ \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\ \\ =3$

Part 2

$7-8\div4(3^2-1)=7-8\div4(9-1) \\ \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\ \\ =6 \frac{1}{2} = \frac{13}{2}$

Part 3

$2-2(2-5)^2+3^2=2-2(-3)^2+9 \\ \\ =2-2(9)+9=2-18+9=-7$

Part 4

$(5^2-9\cdot3)^2-11=(25-27)^2-11 \\ \\ =(-2)^2-11=4-11=-7$

Part 5

$[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\ \\ =(1-5)\cdot4=-4\cdot4=-16$

Part 6

$12-11\cdot2+16\div8=12-22+2 \\ \\ =-8$

Part 7

$-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\ \\ =-2-(-1)=-2+1=-1$

Part 8

$8+2\cdot3-14\div7=8+6-2 \\ \\ =12$

Part 9

$(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\ \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\ \\ =36+4=40$

Part 10

$7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\ \\ =7+(-7)\cdot5=7+(-35)=7-35 \\ \\ =-28$

Part 11

$3-2[2^3+(-1)^3]=3-2[8+(-1)] \\ \\ =3-2(8-1)=3-2(7)=3-14 \\ \\ -11$

Part 12

$18+6\div3(2^2+5)=18+6\div3(4+5) \\ \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\ \\ =18 \frac{2}{9}$

8 0

3 years ago

A rectangular tank with a square base, an open top, and a volume of 8 comma 7888,788 ft cubedft3 is to be constructed of sheet

Vlad [161]

Answer:

26 ft square by 13 ft high

Step-by-step explanation:

The tank will have minimum surface area when opposite sides have the same total area as the square bottom. That is, their height is half their width. This makes the tank half a cube. Said cube would have a volume of ...

2·(8788 ft^3) = (26 ft)^3

The square bottom of the tank is 26 ft square, and its height is 13 ft.

_____

<em>Solution using derivatives</em>

If x is the side length of the square bottom, the height is 8788/x^2 and the area is ...

x^2 + 4x(8788/x^2) = x^2 +35152/x

The derivative of this is zero when area is minimized:

2x -35152/x^2 = 0

x^3 = 17576 = 26^3 . . . . . multiply by x^2/2, add 17576

x = 26

_____

As the attached graph shows, a graphing calculator can also provide the solution.

5 0

3 years ago