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Aliun [14]
4 years ago
6

Greatest common factor of 126

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
6 0

Answer:

7

Step-by-step explanation:

Dovator [93]4 years ago
6 0

Answer:

1

Step-by-step explanation:

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The dwarf planet Eris has no atmosphere and has been easier to measure than Pluto. At its
lesya [120]

Answer:

1.6%

Step-by-step explanation:

2376/2338= 1.016

1.016-1 = .016 * 100

1.6%

hope it helps :)

3 0
3 years ago
In how many ways can 2 Mango, 3 Black berry and 3 Tamarin trees can be planted in a straight
SCORPION-xisa [38]
<span>in how many ways can 2mango, 3 black berry and 3 tamarind trees can be planted in a straight line. if one does not distinguish between trees of the same kind. 9!/(3!3!2!) n! = total ways that's 9. 3! bc there are 3 similar blackberries, 2! bc there are 2 similar mangoes and another 3! bc there are 3 similar tamarind. PS "similar" is the key here.</span>
5 0
4 years ago
18. El equipo de docentes del Área de Formación Humanística decide repartir 195 ejemplares de libros de lectura a 4 estudiantes
irina [24]

Answer:

Each of the students absent for 1, 2, 4 and 5 days get 57, 53, 45 and 40 copies of the the reading books respectively.

Step-by-step explanation:

English Translation

The team of teachers from the Humanistic Training Area decides to distribute 195 copies of reading books to 4 students previously classified on their own merits. But the distribution will be made taking into account absences from classes during the first cycle. How many books does each student receive if their absences have been 1; two; 4 and 5 days, respectively?

Solution

Because the more the number of days absent, the less the number of books each of the 4 students deserve, we have to employ an elaborate scheme.

If 195 copies are distributed equally between 4 People, each person gets 48.75 copies of the books.

Now, if we add another 48.75 copies of books to the total number of books, each person gets 60.9375 books.

But, we can then divide 48.75 extra books on top according to the number of days absent and subtract each person's number from the assumed 60.9375 books, with an extra 48.75 books.

Total number of days absent = 1 + 2 + 4 +5 = 12

(48.75/12) = -4.0625 copies for each absent day.

The student with only 1 absent day gets 60.9375 - 4.0625 = 56.875 copies = 57 copies

The student with 2 absent days, gets = 60.9375 - (2×4.0625) = 52.8125 copies = 53 copies

The student with 4 absent days, gets = 60.9375 - (4×4.0625) = 44.6875 copies = 45 copies

The student with 5 absent days, gets = 60.9375 - (5×4.0625) = 40.425 copies = 40 copies

Hence, each of the students absent for 1, 2, 4 and 5 days get 57, 53, 45 and 40 copies of the the reading books respectively.

Hope this Helps!!!

6 0
3 years ago
I need the distance please
sasho [114]
Use this formula:  d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }

Again :'(

5. d=10

6. d=4

7. d=4
5 0
4 years ago
Need help on these two please
fredd [130]
Your rays are
F
E

Segments
DF
DE
EF
8 0
3 years ago
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