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My name is Ann [436]
3 years ago
11

In an arithmetic sequence {an}, if a1 = 5 and d = 3, the first 4 terms in the sequence are

Mathematics
2 answers:
noname [10]3 years ago
6 0
A1 represents the first term

d represents the common difference.....and since the common difference is 3, u have to add 3 to each term to find the next term....because with an arithmetic sequence u add to find the next term, whereas, in a geometric sequence u multiply to find the next term

5...first term
5 + 3 = 8...2nd term
8 + 3 = 11...3rd term
11 + 3 = 14...4th term

ur answer is B
motikmotik3 years ago
5 0
a_n=a_1+(n-1)d\\\\a_1=5;\ d=3\\\\substitute\\\\a_n=5+(n-1)\cdot3=5+3n-3=3n+2\\\\a_1=3\cdot1+2=5\\a_2=3\cdot2+2=8\\a_3=3\cdot3+2=11\\a_4=3\cdot4+2=14\\a_5=3\cdot5+2=17\\\vdot

Answer:\boxed{B)\ \{5;\ 8;\ 11;\ 14;\ 17;\ ... \} }
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Answer:

Option c

Step-by-step explanation:

given that limit x tending to 4 of the function (3x-4) is 8

This implies for all values of x such that for epsilon >0 arbitrary small ,

||x-4||, we get

|f(x)-8|<3epsilon

this is equivalent to the option c.

Proof:

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Hence it follows that option C is right.

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Setler79 [48]

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8 0
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