Question

Find the 22nd term of the following sequence: 5, 8, 11, ... 63 71 14 68

Answer 1

68 is the 22nd term of the following sequence.

Step-by-step explanation:

• The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the  Arithmetic progression ( AP).
• For finding the nth term in the AP we have a formula tn = a + (n-1) × d
• Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
• Thus here tn = 5 + ( 22 - 1 ) × 3.
• On subtracting we get tn = 5 + (21 ) × 3
• On multiplying we get tn = 5 + 63
• After adding we get tn = 68. It is the 22nd term in the given series.