Find the 22nd term of the following sequence: 5, 8, 11, ... 63 71 14 68

Mathematics

1 answer:

Wittaler [7]4 years ago

5 0

68 is the 22nd term of the following sequence.

<u>Step-by-step explanation:</u>

The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the Arithmetic progression ( AP).
For finding the nth term in the AP we have a formula tn = a + (n-1) × d
Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
Thus here tn = 5 + ( 22 - 1 ) × 3.
On subtracting we get tn = 5 + (21 ) × 3
On multiplying we get tn = 5 + 63
After adding we get tn = 68. It is the 22nd term in the given series.

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