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3 years ago

Find the 22nd term of the following sequence: 5, 8, 11, ... 63 71 14 68

Mathematics

1 answer:

Wittaler [7]3 years ago

5 0

68 is the 22nd term of the following sequence.

<u>Step-by-step explanation:</u>

The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the Arithmetic progression ( AP).
For finding the nth term in the AP we have a formula tn = a + (n-1) × d
Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
Thus here tn = 5 + ( 22 - 1 ) × 3.
On subtracting we get tn = 5 + (21 ) × 3
On multiplying we get tn = 5 + 63
After adding we get tn = 68. It is the 22nd term in the given series.

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Given that g(x)=3x²-5x+7 find the following: <br> g(-x)

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G(x) = 3x² - 5x + 7
g(-x) = -(3x² - 5x + 7)
g(-x) = -3x² + 5x - 7

This equation cannot be solved because of a few reasons,

1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)

-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,

$Solve\ using\ the\ formular\ \ \boxed{ x= { \frac{-b \pm \sqrt{b^2-4ac} }{2a} } }$
a = 3
b = -5
c = 7
$x= { \frac {-(-5) \pm \sqrt{ (-5)^2-4(3)(7) } }{2(3)} }$
$x= { \frac {5 \pm \sqrt{-59} }{6} }$

∴This equation cannot be solved.

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3 years ago

Note Figure is not drawn to scale.

wolverine [178]

Answer:

your answer is...

Step-by-step explanation:

50.265482457437

I used my calculator

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2 years ago

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Rudik [331]

Answer:

Step-by-step explanation:

first angle = x

second angle = x+30

third angle = 4x

x + (x+30) + 4x = 180

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x = 150:6

x = 50

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3 years ago