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kvv77 [185]
3 years ago
6

Find the 22nd term of the following sequence: 5, 8, 11, ... 63 71 14 68

Mathematics
1 answer:
Wittaler [7]3 years ago
5 0

68 is the 22nd term of the following sequence.

<u>Step-by-step explanation:</u>

  • The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the  Arithmetic progression ( AP).
  • For finding the nth term in the AP we have a formula tn = a + (n-1) × d
  • Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
  • Thus here tn = 5 + ( 22 - 1 ) × 3.
  • On subtracting we get tn = 5 + (21 ) × 3
  • On multiplying we get tn = 5 + 63
  • After adding we get tn = 68. It is the 22nd term in the given series.
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Subtract 4/5 from each side of the equation:

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Now it's just problem in plain old adding and subtracting fractions,
just like the ones you've done many times before.

First let's change (2 and 1/3) to a fraction:    2 and 1/3  =  7/3

So you have to find the value of  (7/3) - (4/5) .

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