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Montano1993 [528]
3 years ago
5

Experts please please PLEASE answer this question ASAP! Due today.

Mathematics
1 answer:
quester [9]3 years ago
8 0

The height of the given trapezoid is 7.5 m.

Step-by-step explanation:

Step 1:

The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.

The trapezoid's area, A = \frac{b_{1}+b_{2}}{2} (h).

Here b_{1} is the lower base length and b_{2} is the upper base length while h is the height.

Step 2:

In the given problem, b_{1}=5 \mathrm{m} and b_{2}=3 \mathrm{m}. Assume the height is h m.

The trapezoid's area = 30.

30 = \frac{5+3}{2} (h), 30 = (4)(h).

h = \frac{30}{4} = 7.5.

So the height of the given trapezoid is 7.5 m.

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Which of the following probabilities is equal to approximately 0. 2957? Use the portion of the standard normal table below to he
Travka [436]

Probability of an event is the measure of its chance of occurrence. The event out of the listed events whose probability is 0.2957 is given by : Option C: P(0.25 \leq Z \leq 1.25)

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z-score.

If we have

X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation \sigma )

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z tables, the p-value we get is

P(Z \leq z) = \rm p \: value

Using the z-table, we get the needed probabilities as:

Case 1:

P(-1.25 \leq Z \leq 0.25) = P(Z \leq 0.25) - P(Z \leq -1.25) \approx 0.5987 - 0.1056 = 0.4931

Case 2:

P(-1.25 \leq Z \leq 0.75) = P(Z \leq 0.75) - P(Z \leq -1.25) \approx 0.7734- 0.1056=0.6678

Case 3:

P(0.25 \leq Z \leq 1.25) = P(Z \leq 1.25) - P(Z \leq 0.25) \approx 0.8944 - 0.5987=0.2957

Case 4:

P(0.75 \leq Z \leq 1.25) = P(Z \leq 1.25) - P(Z \leq 0.75) \approx 0.8944 - 0.7734 =0.1210

Thus, the event out of the listed events whose probability is 0.2957 is given by : Option C: P(0.25 \leq Z \leq 1.25)

Learn more about z-scores here:

brainly.com/question/13299273

5 0
2 years ago
(4 x 300) + (4 x 25)
Dominik [7]

Answer:

1,300

Step-by-step explanation:

Order of operations tells us that we should do everything in parentheses first.

Multiplying out (4 x 300) and (4 x 25) gets

1200 + 100

From here, we add the two together to arrive at

1,300

3 0
3 years ago
Read 2 more answers
of 320 consumers polled, some purchase blu-ray movies, some only purchase movies on dvd, and some do both. if 300 people polled
Helga [31]

Answer:

20 people only buy dvds.

Step-by-step explanation:

There are two groups in this problem. One group of people that buys dvds and one that buys blu rays. The total amount of people who buy blu rays is 300, but there's an intersection between the groups and the size of this is 280 people who actually buy both. In order to find out how many people only buy DVDs we first need to figure out how many only buy blu-rays. That is:

people who only buy blu rays = people who buy blu rays - people who buys blu rays and dvds

people who only buy blu rays = 300 - 280 = 20

We can now calculate the amount of people who only buy dvds and that is:

people who only buy dvds =total amount of people - ( people who only buy blu rays + people who buy both)

people who only buy dvds = 320 - (20 + 280) = 320 - 300 = 20 people

3 0
3 years ago
Solve the proportion x+1/3 = x/2<br><br> 5<br> 1<br> 2<br> 10
s344n2d4d5 [400]

Value of x is 2.

Step-by-step explanation:

  • Step 1: Given that x+1/3 = x/2

Cross-multiply to find the value of x.

⇒ 2(x + 1) = 3x

⇒ 2x + 2 = 3x

⇒ x = 2

4 0
3 years ago
A randomly generated list of integers from 0 to 4 is being used to simulate an event, with the numbers 1, 2, and 3 representing
Tresset [83]

Answer:

I think the anwser is

<h2>C.60 percent</h2>

hope it helped

6 0
3 years ago
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