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ira [324]
3 years ago
5

What is the coefficient of the x^4 term in the expanded form of (2x-7)^6

Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:

The coefficient of x^{4} = 11760

Step-by-step explanation:

∵ The rule of expanded the binomial is :

(a+b)^{n}=C_{0} ^{n} a^{n}b^{0}+C_{1}^{n}a^{n-1}b^{1}+C_{2}^{n}a^{n-2}b^{2}+.............

∴ The Expanded of (2x-7)^{6} is:

(2x-7)^{6}=C_{0}^{6}(2x)^{6}(-7)^{0}+C_{1}^{6}(2x)^{5}(-7)^{1}+C_{2}^{6}(2x)^{4}(-7)^{2}+..........

(2x-7)^{6}=(1)(64x^{6})(1)+(6)(32x^{5})(-7)+(15)(16x^{4})(-7)^{2}

We will take the term of x^{4} and find the coefficient of it

∴ The coefficient of x^{4} = (15)(16)(-7)^{2}=(15)(16)(49)=11760

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