Answer:
Verify x+y+z)=(x+y)+z for the following values of x,y,z
(i)x=3/4,y=5/6,z=-7/8(
ii)x=2/; 3,y=-5/6,z=-7/9(
iii)x=3/5,y=-6/9,z=2/10(
iv)x=; - 3/5, y = - 7/10, z = - 8/15 To Verify x+(y+z)=(x+y)+z (i)x=3/4,y=5/6,z=-7/8 LHS = 3/4 + (5/6 + (-7/8)) = (3/4) + (5/6 -7/8)= (3/4) + ((20-21)/24) = 3/4 - 1/24 =(18-1)/24 = 17/24
RHS = (3/4 + 5/6) + (-7/8)= (9 + 10)/12 - 7/8 = 19/12-7/8 = (38-21)/24 = 17/24
LHS = RHS = 17/24 (ii) * x = 2/3, y = - 5/6, z = - 7/9 LHS = 2/3 + (-5/6+ (-7/9) = 2/3 + (-5/6 - 7/9) = 2/3 + (-29/18) = 2/3 - 29/18
= 12/18 - 29/18 = -17/18
RHS = (2/3 + (-5/6))+(-7/9) = (2/3 - 5/6) - 7/9 = (-1/6) - 7/9 = -1/6 - 7/9 = -3/18 - 14/18 =
-17/18
LHS = RHS....
Hence verified..
Step-by-step explanation:
hope it helps u no notebook
.???
Answer:
168 in²
Step-by-step explanation:
The square would be 36 in²
Area of a triangle is A= 1/2 bh
A = 1/2 (11 x 6), A= 1/2 (66)
1/2 (66) = 33 in², which is the area of a triangle.
Then you multiply 33 x 4 to get the area of all the triangles, which is 132 in²
You add the area of the square to the area of the triangles, which is 168 in².
Answer:
489.84 m²
Step-by-step explanation:
Area of one 2d circle: πr² ⇒ π6² ⇒ 36π ≈ 113.04 (using 3.14 for pi)
Area of both 2d circles: 113.04 + 113.04 =226.08 m²
Now we have to find the width of the rectangle, which is equal to the circumference of either circle:
Width of rectangle: 2πr ⇒ 2π6 = 12π ≈ 37.68 (using 3.14 for pi)
We can find the area of the rectangle now, since the length was given
Area of rectangle: 37.68· 7= 263.76 m²
Surface Area: 263.76+226.08= 489.84m²
Hopefully this helps!
For this case, the first thing we must do is calculate the total cost.
We have then:
C = (16) * (2.4) * (6)
C = 230.4 $
Then, the change it receives is given by:
250 - 230.4 = 19.6 $
Answer:
He has received 19.6 $ from $ 250