Your answer is Bertrand Russel
when solving for y
y = -7x/3-6
so y does not vary directly with x
the answer is no
Answer: √(f^2 - 2f + 1) = a
Step-by-step explanation:
We have that:
f^2+g^4-2f+1 = a^2+(g^2)^2
And we want to find the value of a, so we should isolate it.
f^2 + g^4 - 2f + 1 = a^2 + g^(2*2) = a^2 + g^4
where i used that (x^y)^z = x^(y*z)
We can remove the term g^4 in both sides of the equation and get:
f^2 - 2f + 1 = a^2
now we can apply the square rooth to both sides and get
√(f^2 - 2f + 1) = a
So we just found the value of a.
13
hope this helps plz mark me as brainliest
im in middle school so im not 101% sure but i am confident in my answer so please... no h8
