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Rina8888 [55]
3 years ago
12

1, 4, 13, 40, 121 what is the next number in the pattern

Mathematics
1 answer:
mart [117]3 years ago
7 0
Add powers of 3.
1 + 3 = 4
4 + 9 = 13 = 4 + 3^2
13 + 27 = 40 = 13 + 3^3
40 + 81 = 121 = 40 + 3^4
Now you need to add 3^5 to 121.

121 + 3^5 = 121 + 243 = 364
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What is the area of a regular octagon with a side length of 6 mm and an apothem length of 7.243 mm? Round your answer to the nea
Harlamova29_29 [7]
OCTA=8, an octagon has 8 sides, thus if one side is 6mm, then all sides, namely the perimeter, is 6+6+6+6+6+6+6+6, or 48.

now, we know what the apothem is.

\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{2}ap~~
\begin{cases}
a=apothem\\
p=perimeter\\
-------\\
p=48\\
a=7.243
\end{cases}\implies A=\cfrac{1}{2}(7.243)(48)
5 0
3 years ago
Please help I don’t think I remember this
nikdorinn [45]

Answer:

im not sure if this is right

Step-by-step explanation:

demension 1: 9 X 10      demension 2: 10 x 4

4 0
3 years ago
Read 2 more answers
In a fitness program, Pedro does 20 sit-ups on the first day, and increases this by 2 sit-ups everyday. Determine the day when t
Fittoniya [83]

Answer:

day 540

Step-by-step explanation:

He increases his number of situps by 2 each day meaning on day 1 he'd do 2 extra, on day 2 he'd do 4 extra, on day he'd do 6 extra etc. We can show this by saying +2x where x is the day he is on.  Then since he started with 20 we have to add 20 so it would be 20+2x.  We want to know what day it is when he does 1100 situps so we can set our equation equal to 1100 and solve for X which is the day it would be.

20+2x=1100

2x=1080

I hope this helps and please don't hesitate to ask if there is anything still unclear!

x=540

5 0
3 years ago
Quick please no links or anything just the straight up answer answer both please
zlopas [31]
For 27) D
For 28) A
Hope that helps!
8 0
3 years ago
Read 2 more answers
Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
3 years ago
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