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Artyom0805 [142]
3 years ago
6

The team manager mixes 0.6 kg of Gatorade powder in water of 5 gallon.Gatorade donate new 7 gallon water jug.How much powder sho

uld the manager use in the 7 gallon water to make the same Gatorade mixture?In kg
Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer:

The amount of powder the manager should use in 7 gallon water to make the same Gatorade mixture is 0.84 kg

Step-by-step explanation:

Here we have that the quantity of Gatorade powder the manager is mixing per 5 gallon of water = 0.6 kg

Quantity of Gatorade powder per 1 gallon of water = 0.6/5 kg = 0.12 kg

Where, by the Gatorade donates a new 7 gallon water jug and the manager will make the same mixture, we will have;

Quantity of Gatorade powder per 7 gallon of water = 7 × 0.12 kg = 0.84 kg

Therefore, the amount of powder the manager should use in 7 gallon water to make the same Gatorade mixture = 0.84 kg.

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Answer:

Angle A= 77.14°

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Step-by-step explanation:

Supplementary angles are angles that add up to 180°, as stated in the question.

This means that Angle A + Angle B= 180°

The measure of Angle A to Angle B is 3:4

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Hence, angle A will be 3/7 of the total angle (180°)

angle B will be 4/7 of the total angle (180°)

That is, angle A = 3/7 × 180° = 77.1428°

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