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mestny [16]
3 years ago
8

-2 3/4 + (-1 1/3) I need this for a test pls help

Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:

-77/12,    -6 5/12,    or   -6.416

Step-by-step explanation:

convert

calculate

done

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What is the sum of ∞Σn=1 2(1/5)^n-1? s=1/5 s=2/5 s=5/3 s=5/2
lutik1710 [3]

The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

<h3>How to determine the sum of the notation?</h3>

The sum notation is given as:

∞Σn=1 2(1/5)^n-1

The above notation is a geometric sequence with the following parameters

  • Initial value, a = 2
  • Common ratio, r = 1/5

The sum is then calculated as

S = a/(1 - r)

The equation becomes

S = 2/(1 - 1/5)

Evaluate the difference

S = 2/(4/5)

Express the equation as products

S = 2 * 5/4

Solve the expression

S= 5/2

Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

Read more about sum notation at

brainly.com/question/542712

#SPJ1

7 0
1 year ago
Graph a line parallel to y-2x+1 and has a y-intercept of (0,5))
Debora [2.8K]

your answer is x = 6

desmos

7 0
2 years ago
Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac
TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

6 0
11 months ago
Which of the following is an equation of the line that crosses through (-3,4) and (3,6)?
Mama L [17]

Answer:

y=(1/3)x+5

Step-by-step explanation:

Slope-intercept: y=mx+b

m=((y2-y1)/(x2-x1)) = (6-4)/(3+3)= 2/6= (1/3)

y=(1/3)x+b

plug in one of the points (3,6)

6=(1/3)(3)+b

6=1+b    5=b

6 0
3 years ago
What is the perimeter of a rectangle with a length of (x^2+x) and a width of (2x^2+3x)
Mazyrski [523]

Answer:

Perimeter = 6x² + 8x

Step-by-step explanation:

Perimeter = 2(length + width)

perimeter = 2((x²+x)+(2x²+3x))

perimeter = 2(x²+2x² + x+3x)

perimeter = 2(3x² + 4x)

perimeter = 2*3x² + 2*4x

perimeter = 6x² + 8x

5 0
3 years ago
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