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3 years ago

What is the correct solution to 1/2(x+18)=4(2x-6)-9x

Mathematics

1 answer:

denis-greek [22]3 years ago

4 0

Answer:

x = 22

Step-by-step explanation:

I interpreted your problem as:

$\frac{1}{2} (x+18) = 4(2x-6)-9x$

I simplified the problem to:

$\frac{1}{2} x+9 = 8x-24-9x$

I combined like terms:

$\frac{1}{2} x+9 = -x-24$

I moved all x to one side and all other constants to the other:

$\frac{3}{2} x = -33$

I divided by 3/2 (1.5) on both sides to isolate x:

$x = 22$

Hope it helps! (:

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pav-90 [236]

Answer:

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Step-by-step explanation:

9+x-7≥ 21

Combine like terms

2+x≥21

Subtract 2 from each side

2+x-2 ≥21-2

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3 years ago

I need my smart homies to answer this question for me !

ella [17]

Answer:

Part A: chosen method is by factoring

Part B: First rewrite the equation by writing -24 as a difference so you get x² -9x - 15x + 135 = 0. Then factor out the x and the -15 from the equation so you get x(x-9) - 15(x-9) = 0. Then factor out x-9 from the equation so you have (x-9)(x-15) = 0. Finally, set each expression to 0: x-9=0 and x-15=0 and then solve: x=9 and x=15

Part C: x=9, x=15

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3 years ago

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neonofarm [45]

25-23.08=1.92

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3 years ago

En la fábrica de Don Toño hoy fabricaron 320 pantalones, si los guardan en cajas donde caben 50 ¿cuántas cajas llenaron?

Scrat [10]

Answer:

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Step-by-step explanation:

320/50 = 6.4 Cajas

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3 years ago

Jamal is making two paintings using canvases that are similar rectangles. The length of the smaller canvas is 3 ft and the width

Alex787 [66]

Let's start with what we know:

Smaller canvas:
Length ( $L_{1}$ ) = 3ft
Width ( $W_{1}$ ) = 5ft

Larger canvas:
Length ( $L_{2}$ ) = ?
Width ( $W_{2}$ ) = 10ft

Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:

$\frac{ L_{1} }{ L_{2} } = \frac{ W_{1} }{ W_{2} }$
So let's plug it all in from above:

$\frac{ 3 }{ L_{2} } = \frac{ 5 }{ 10 }$
Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:

$(3)(10) = (5)(L_{2})$
$30 = 5L_{2}$
Now divide each side by 5 to isolate $L_{2}$

$\frac{30}{5} = \frac{ 5L_{2}}{5}$
The 5s on the right cancel out, leaving us with:

$6 = L_{2}$

So the length of the larger canvas is 6 ft

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3 years ago

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