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3 years ago

Find AB when given angle B 64 degress angle C 75 degrese and side a 19

Mathematics

1 answer:

jeka943 years ago

4 0

Answer:

about 28

Step-by-step explanation:

you have to use the sine rule = side you know * ( sin of angle opposing the side you want to know / sin of angle opposing the side you know)

AB = 19* (sin 75/ sin ( 180 -75-64) )

AB = 19 * ( sin 75 / sin 41) ≈ 27.9739...

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If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago

At sea level, earths atmosphere exerts a pressure of 1 atmosphere. Atmospheric pressure P (in atmospheres) decreases with altitu

PtichkaEL [24]

Answer:

Initial Amount=1

Decay Factor=0.99987

Decay Rate=0.013%

Step-by-step explanation:

If P = 0.99987ᵃ

I. Initial amount

The initial amount is when a=0

P = 0.99987⁰ = 1

The Pressure at Sea Level=1

II. Decay factor

This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.

III. Decay Rate = 1-0.99987 = 0.00013

Expressed in Percentage = 0.013%

5 0

3 years ago

Read 2 more answers

If you can tell me the answer please do i need help besties

DerKrebs [107]

Answer:

Step-by-step explanation:

8.5/1

and

x/6

cross multiply

51=x

7 0

3 years ago

Help me please!! it's due today

Bess [88]

Answer:

the answer would be 14-16=-2

Step-by-step explanation:

first u look where the first long arrow goes on this problem then you follow the second arrow which stops at 6 then u count how much until negative 2. but how I did it is the form 14 how much to 0 which is 14 the I count how many until I get to -2 and there's the answer

3 0

3 years ago

Can you please help me, this quiz is timed: 2^3 + 3^3 =

Step2247 [10]

Answer:

Showing da work!

2³+3³

=8+3³

=8+27

=35

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*rate this answer and say thanks please!

5 0

3 years ago