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Daniel [21]
3 years ago
13

If you are given a part-to-whole ratio, can you write part-to-part ratio? Explain

Mathematics
1 answer:
stealth61 [152]3 years ago
8 0

There are 2 types of ratios: Part-to-Wholes, and Part-to-Part ratios.

Part-to-part ratios show the relationship between the two groups.

Lets say theres 10 fruits in a fruit bowl.

If you have 3 apples, and 7 oranges, then the ratio is 3:7 as the part-to-part ratio. But the part-to-whole ratio would be either 3:10 ( for apples) or 7:10 (for oranges)

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Answer:

B.

Step-by-step explanation:

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3 years ago
Four students sold lemonade after school. They had five $5 bills, two $10 bills, seven $1 bills and four dimes. They split the m
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They each got 4 dollars because all the $ added up will be 16 and it divided by the 4 kids 16 •|• 4= 4
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Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D
-Dominant- [34]

By iteratively substituting, we have

a_n = a_{n-1} + n

a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)

a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)

and the pattern continues down to the first term a_1=0,

a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))

\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)

\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k

Recall the formulas

\displaystyle \sum_{n=1}^N 1 = N

\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2

It follows that

a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2

\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1

\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}

4 0
2 years ago
(2.5×10^−10)(7×10^−6)
Nataly [62]
<span>(2.5×10^−10)(7×10^−6) 
= (2.5 x 7) (</span>10^−10 x 10^−6)
= 17.5 x 10^-16
= 1.75 x 10^-15

answer
<span>B. 1.75×10^−15 </span>
6 0
3 years ago
4 pounds of grapes cost $11.52. what is the unit rate?
Zepler [3.9K]

Answer: 2.88/1

Step-by-step explanation:

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