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3 years ago

Which of the binomials below is a factor of this trinomial? 4x2 + 12x + 9

Mathematics

1 answer:

Furkat [3]3 years ago

8 0

The correct answer is C tell me if I’m wrong please so I can correct my mistake

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There are 15 marbles in a bag: 7 are blue, 6 are white, and 2 are green. If one marble is drawn, what is the probability that it

DIA [1.3K]

40% white
13.33% green

6 0

3 years ago

PLEASE HELP

ruslelena [56]

Answer:

Rosaria purchased 50 bracelets and 70 necklaces

Step-by-step explanation:

Let the number of bracelets be b and the number of necklaces be n

b + n = 120 •••••(i)

Secondly;

10b + 11n = 1270 ••••(ii)

Total cost of b bracelets at 10 per 1 is 10b

Total cost of n bracelets at 11 per 1 is 11n

Adding both gives 1270

From i, b = 120-n

Substitute this into ii

10(120-n) + 11n = 1270

1200 - 10n + 11n = 1270

n = 1270-1200

n = 70

b = 120-n

b = 120-70

b = 50

4 0

3 years ago

HELP!!!! Choose the correct answer. Which expression, when evaluated,

blagie [28]

We will check each options and verify it

(a)

$18-2m$

we can plug m=2

$18-2\times 2$

$18-4$

$14$

so, this is FALSE

(b)

$7x-\frac{x}{3} >19$

we can plug x=3

$7\times 3-\frac{3}{3} >19$

$21-1 >19$

$20 >19$

so, this is TRUE

(c)

$6x-1>4x+5$

we can plug x=3

$6\times 3-1>4\times 3+5$

$18-1>12+5$

$17>17$

so, this is FALSE

(d)

$2x^2-3x+1$

now, we can plug x=2

$2(2)^2-3(2)+1$

$8-6+1$

$3$

So, this is FALSE

8 0

3 years ago

PLEASEEE HELPPPP!!!!!!!!!skkaksks

Vesnalui [34]

Step-by-step explanation:

(√3+√7)(√3+√7)
(√3)^2+[(√3*√7)+(√3*√7)]+(√7)^2
3+2√21+7
10+2√21

6 0

2 years ago

Simplify 1- cos^2 Θ / cos^2 Θ Answers sin2 θ cos2 θ tan2 θ 1

Tems11 [23]

Answer:

Trigonometric identities

$\large \begin{aligned}\cos^2 \theta + \sin^2 \theta & = 1\\\implies \quad \quad \sin^2 \theta & = 1 - \cos^2 \theta\\\\\tan \theta=\dfrac{\sin \theta}{\cos \theta} \end{aligned}$

Therefore, using the identities, the given expression can be simplified as follows:

$\large\begin{aligned}\implies \dfrac{1- \cos^2 \theta}{\cos^2 \theta} & = \dfrac{\sin^2 \theta}{\cos^2 \theta}\\\\& = \tan^2 \theta\end{aligned}$

3 0

2 years ago

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