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makvit [3.9K]
2 years ago
11

Find the sum of the first 50 terms. 10-2/11n

Mathematics
1 answer:
Alexus [3.1K]2 years ago
6 0

Answer:

in picture

yw :D

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algebraically determine the values of h and k to correctly complete the identity stated below : 2 x cubed - 10x squared + 11x -
11Alexandr11 [23.1K]

Answer:

The values for expression is h = - 2 and k = 5

Step-by-step explanation:

Given algebraic expression can be written as :

2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k

Now opening the bracket

Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3  ) + k

Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12  +k

Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12  + k

Now, equating the equation both sides

I.e  - 10 =  ( h - 2 )

Or , h - 2 = - 10

I.e , h = - 10 + 2

∴ h = - 2

Again , 11  = ( 3 - 4 h )

or, 11 = 3 - 4 h

or, 11 - 3 = - 4 h

or, 8 = - 4 h

∴ h = \frac{-8}{4}

I.e h = - 2

Again

- 7 = - 12 + k

Or, k = - 7 + 12

∴  k = 5

Hence The values for expression is h = - 2 and k = 5    . Answer

5 0
3 years ago
What is the rate of change?<br> the second 1 and second 4?
Mumz [18]
Idek but I do know that 12x8= 72
5 0
3 years ago
Please help me pleasssseeee &lt;3
Sophie [7]

Answer:

1st ans

(8x+19)=(9x+9)(vertically opposite angle)

19-9=9x-8x

x=10

2nd ans

(3x-31)=(x+59)(exterior alternate angle)

3x-x=59+31

2x=90

x=90/2

x=45

3rd ans

(5x-33)+(6x+4)=180(straight angle )

11x-29=180

11x=180+29

x=209/11

x=19

8 0
3 years ago
10^-3<br> it told me i needed to write more characters
Katen [24]

try .01

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
i think of a number. if i divide the sum of 6 and the number by 3, the result is 4 more than one quarter of the number. find the
slega [8]

Answer:

-12

Step-by-step explanation:

Let the number be A

Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A

That’s

6+A/3 = 4+1/4 of A

6+A/3 = 4+1/4 x A

6+A/3 = 4+A/4

Cross multiply

4(6 + A) = 3(4 + A)

Distribute

4 x 6 + 4 x A = 3 x 4 + 3 x A

24 + 4A = 12 + 3A

Subtract 24 from both sides to eliminate 24 on the left side

24 - 24 + 4A = 12 - 24 + 3A

4A = -12 + 3A

Subtract 3A from both sides so the unknown can be on one side

4A - 3A = -12 + 3A - 3A

A = -12

Check

6+(-12)/3 = 4 +(-12)/4

6 -12/3 = 4 -12/4

-6/3 = -8/4

-2 = -2

6 0
3 years ago
Read 2 more answers
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