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3 years ago

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A brick has a mass of 100g and a volume oh 25cm3.what is the density of the brick

1 answer:

Tcecarenko [31]3 years ago

3 0

Density is defined as mass divided by volume, therefore: 100g/25cm3 = 4 g/cm3

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$\textsf {\large{\underline { \underline {SOLUTION:-}}}}$

⇰Let O be the point of observation on the ground OX.

⇰Let A and B be the two positions of the jet.

$\bf➠Then, \angle XOA=60⁰ \: and \: \angle \: XOB=30⁰ \\ \\$

$\bf ➠Draw \: AL \perp \: OX \: and \: BM \perp \: OX \\ \\$

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$\bf = \huge( \small \: 720 \times \frac{5}{18} \huge) \small \: m / s\\$

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$\bf \therefore LM=AB=3000m \\ \\$

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$\bf \implies \: x = \frac{h}{ \sqrt{3} } \: \: \: \: \: \: \: ....(1) \\ \\$

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$\bf\frac{OM}{BM} =cot30⁰= \sqrt{3} \\ \\$

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$\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m \: and \: BM=h \: m]}$

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$\bf \implies \: x = ( \sqrt{3} h - 3000) \: \: \: \: \: \: ....(2) \\$

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$\bf \: \sqrt{3} h - 3000 = \frac{h}{ \sqrt{3} } \\ \\$

$\implies \bf \: 3h - 3000 \sqrt{3} = h \\$

$\bf \implies \: 2h = (3000 \times \sqrt{3} ) = (3000 \times 1.762) \\$

$\bf \implies \: h = (3000 \times 0.866) = 2598 \\ \\$

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