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dezoksy [38]
4 years ago
5

Owen plots the numbers 4, –6, –8, and –3 on a horizontal number line. Which list shows the numbers in the order in which they wo

uld appear from left to right on the number line?

Mathematics
1 answer:
Maru [420]4 years ago
4 0

Answer:

-8  -6   -3   4

Step-by-step explanation:

In a number line, the numbers on the are lesser than the numbers on the right. In a number line with integers, numbers going to the right from the midline which is 0 is positive and increases as you move to the right. As you move to the left, the numbers are negative and decreases as you move further to the left.

Attached is a picture of how it would look on a number line.

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Solve the equation y + 5=-12 <br> A y=-19<br> B y=-17<br> C y=-7<br> D y=7
mrs_skeptik [129]

Answer:

y=17

Hope this helps you

8 0
3 years ago
Read 2 more answers
For f(x) = 4x + 2 and g(x) = x^2 - 6, find (f+g)(x)
Margaret [11]

Answer:

(f+g)(x) = x^2 + 4x - 4

Step-by-step explanation:

We are given these following functions:

f(x) = 4x + 2

g(x) = x^2 - 6

(f+g)(x)

We add the common terms. Thus:

(f+g)(x) = f(x) + g(x) = 4x + 2 + x^2 - 6 = x^2 + 4x + 2 - 6 = x^2 + 4x - 4

Thus:

(f+g)(x) = x^2 + 4x - 4

3 0
3 years ago
PLEASE HELP !!!!!!!!!! I'LL GIVE BRAINLIST!!!!!!
aleksandr82 [10.1K]
It is 189 the answer
5 0
3 years ago
Read 2 more answers
Which of the following shows the division problem below in synthetic division form? (6x^3+x^2-3)/(x-7)
PSYCHO15rus [73]

Answer:

Option C.

Step-by-step explanation:

If a polynomial P(x) is divided by (x-c), then we write leading coefficients inside the synthetic division line and c outside the synthetic division line.

The given division problem is

\dfrac{6x^3+x^2-3}{x-7}

Here,

x-c=x-7\Rightarrow c=7

The numerator polynomial can be written as

P(x)=6x^3+x^2+0x-3

So, the coefficients of numerator are 6, 1, 0, -3.

The synthetic division form for given division problem is

7      |     6       1      0    -3

Therefore, the correct option is C.

5 0
3 years ago
Setting:
nata0808 [166]
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.

b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.

c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%

6 0
3 years ago
Read 2 more answers
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